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3 years ago

How is an equation different from an inequality

Mathematics

2 answers:

Andrei [34K]3 years ago

6 0

Answer:

Step-by-step explanation:

1. An equation is a mathematical statement that shows the equal value of two expressions while an inequality is a mathematical statement that shows that an expression is lesser than or more than the other. ... An equation shows the equality of two variables while an inequality shows the inequality of two variables.

Goryan [66]3 years ago

3 0

Answer: Equations and inequalities are both mathematical sentences formed by relating two expressions to each other. In an equation, the two expressions are deemed equal which is shown by the symbol =. Where as in an inequality, the two expressions are not necessarily equal which is indicated by the symbols: >, <, ≤ or ≥.

Step-by-step explanation:

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Mila [183]

First we need to have same units before comparing them. That is, either both of them are in cm or both of them are in mm. So if we need to convert 12.5 cm to mm, we know that 1 cm =10 mm. So we have to find out how many mm are in 12.5 cm. And let 12.5 cm =x mm. So to find the value of x , we set a proportion and solve for x. That is

$\frac{1cm}{10mm}=\frac{12.5cm}{x mm}$

The units cancel out and we do cross multiplication. That is

$1*x =12.5*10$

x=125

So 12.5 cm =125 mm. Therefore the correct proportion is C.

3 0

3 years ago

Expand and simplify (x+5)(x-2)

salantis [7]

Answer:

${x}^{2} - x - 12 = (x + 3)(x - 4)$

${x}^{2} + 3x + 2 = (x + 2)(x + 1)$

${x}^{2} + 3x - 10 = (x + 5)(x - 2)$

Step-by-step explanation:

F [First terms] - Multiply the first terms in each set of parentheses FARTHEST TO THE LEFT

O [Outside terms] - Multiply the first term in the first set of parentheses FARTHEST TO THE LEFT by the last term in the second set of parentheses FARTHEST TO THE RIGHT

I [Inside terms] - Multiply the last term in the first set of parentheses FARTHEST TO THE RIGHT by the first term in the second set of parentheses FARTHEST TO THE LEFT

L [Last terms] - Multiply the last terms in each set of parentheses FARTHEST TO THE RIGHT

${x}^{2} - x - 12 = {x}^{2} - 4x + 3x - 12$

${x}^{2} + 3x + 2 = {x}^{2} + x + 2x + 2$

${x}^{2} + 3x - 10 = {x}^{2} - 2x + 5x - 10$

I am joyous to assist you anytime.

8 0

2 years ago

(sinx-1)(sinx+cos^2x) multiply and simplify

sveta [45]

$\bf [sin(x)-1][sin(x)+cos^2(x)]\\\\
-------------------------------\\\\
sin^2(x)+sin(x)cos^2(x)-sin(x)-cos^2(x)
\\\\\\\
[sin^2(x)-cos^2(x)]+[sin(x)cos^2(x)-sin(x)]
\\\\\\
-[cos^2(x)-sin^2(x)]-[sin(x)-sin(x)cos^2(x)]
\\\\\\
-[\stackrel{cos(2x)}{cos^2(x)-sin^2(x)}]-sin(x)\stackrel{sin^2(x)}{[1-cos^2(x)]}
\\\\\\
-cos(2x)-sin(x)sin^2(x)\implies -cos(2x)-sin^3(x)$

7 0

2 years ago

Help help help pls :)

kykrilka [37]

Answer:

$opposite\approx 70.02$

Step-by-step explanation:

The triangle in the given problem is a right triangle, as the tower forms a right angle with the ground. This means that one can use the right angle trigonometric ratios to solve this problem. The right angle trigonometric ratios are as follows;

$sin(\theta)=\frac{opposite}{hypotenuse}\\\\cos(\theta)=\frac{adjacent}{hypotenuse}\\\\tan(\theta)=\frac{opposite}{adjacent}$

Please note that the names ( $opposite$ ) and ( $adjacent$ ) are subjective and change depending on the angle one uses in the ratio. However the name ( $hypotenuse$ ) refers to the side opposite the right angle, and thus it doesn't change depending on the reference angle.

In this problem, one is given an angle with the measure of (35) degrees, and the length of the side adjacent to this angle. One is asked to find the length of the side opposite the (35) degree angle. To achieve this, one can use the tangent ( $tan$ ) ratio.