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2 years ago

Solve for missing variables on these two seperate questions.

Mathematics

2 answers:

Iteru [2.4K]2 years ago

8 0

Answer:?

Step-by-step explanation:

malfutka [58]2 years ago

4 0

Answer:

Step-by-step explanation:

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Answer true or false for 1-10 (picture above)

Softa [21]

$\sqrt{a\cdot b}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{a+b}\leq\sqrt{a}+\sqrt{b}\\\\\sqrt{a-b}\geq\sqrt{a}-\sqrt{b}\\----------------------\\1)\ \sqrt{72}=\sqrt{9\cdot8}=\sqrt{9}\cdot\sqrt{8}\qquad TRUE\\\\2)\ \sqrt{13-5}=\sqrt{13}-\sqrt5\qquad FALSE\\\\3)\ \sqrt{9\cdot10}=\sqrt9+\sqrt{10}\qquad FALSE\\\\4)\ \sqrt{18bx}=\sqrt{18}\cdot\sqrt{b}\cdot\sqrt{x}\qquad TRUE\ if\ b\geq0\ and\ x\geq0\\\\5)\ \sqrt{8\cdot12}=\sqrt8\cdot\sqrt{12}\qquad TRUE\\\\6)\ \sqrt{m+x}=\sqrt{m}+\sqrt{x}\qquad FALSE$

$7)\ \sqrt{100+64}=\sqrt{100}+\sqrt{64}\qquad FALSE\\\\8)\ \sqrt{30}=\sqrt{5\cdot6}=\sqrt5\cdot\sqrt6\qquad TRUE\\\\9)\ \sqrt{44}=\sqrt{22+22}=\sqrt{22}+\sqrt{22}\qquad FALSE\\\\10)\ \sqrt{10\cdot10}=\sqrt{10}\cdot\sqrt{10}\qquad TRUE$

3 0

3 years ago

The expression

mafiozo [28]

Answer:

(2) x2+1+4/x+2

Step-by-step explanation:

I hope i am right sorry if i am wrong.

4 0

3 years ago

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round y

kupik [55]

Answer:

75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5 pounds.

Step-by-step explanation:

The question is missing. It is as follows:

Adult wild mountain lions (18 months or older) captured and released for the first time in the San Andres Mountains had the following weights (pounds): 69 104 125 129 60 64

Assume that the population of x values has an approximately normal distribution.

Find a 75% confidence interval for the population average weight μ of all adult mountain lions in the specified region. (Round your answers to one decimal place.)

75% Confidence Interval can be calculated using M±ME where

M is the sample mean weight of the wild mountain lions ( $\frac{69 +104 +125 +129+60 +64}{6} =91.8$ )

ME is the margin of error of the mean

And margin of error (ME) of the mean can be calculated using the formula

ME= $\frac{t*s}{\sqrt{N} }$ where

t is the corresponding statistic in the 75% confidence level and 5 degrees of freedom (1.30)

s is the standard deviation of the sample(31.4)

N is the sample size (6)

Thus, ME= $\frac{1.30*31.4}{\sqrt{6} }$ ≈16.66

Then 75% confidence interval is 91.8±16.66. That is between 75.1 and 108.5

3 0

3 years ago

Using a calculator change2 11/16 into a decimal

Natali [406]

Hey You!

2 11/16 = 2.6875 as a decimal.

That's Your Answer! ^

3 0

3 years ago

Read 2 more answers

Construct a sample (with at least two different values in the set) of 4 measurements whose mean, median, and mode are equal. If

KiRa [710]

Answer:

The first set 4 , 6 , 6 , 8

The second set 2 , 6 , 6 , 10

Step-by-step explanation:

Mean is the average of the values in a set. This can be found by summing all the numbers and dividing by the total number. The median is the middle number when the values are listed in order of increasing size. The mode is the number(s) that appear the most often in the set.

The first set 4 , 6 , 6 , 8

mean = (4 + 6 + 6 + 8 )/4 = 6

median = (6+6)/2 = 6

Mode = 6

The second set 2 , 6 , 6 , 10

mean = (2 + 6 + 6 + 10)/4 = 6

median = (6+6)/2 = 6

Mode = 6

3 0

3 years ago