Answer:
20 ft by 60 ft
Step-by-step explanation:
"What should the dimensions of the garden be to maximize this area?"
If y is the length of the garden, parallel to the stream, and x is the width of the garden, then the amount of fencing is:
120 = 3x + y
And the area is:
A = xy
Use substitution:
A = x (120 − 3x)
A = -3x² + 120x
This is a downward facing parabola. The maximum is at the vertex, which we can find using x = -b/(2a).
x = -120 / (2 · -3)
x = 20
When x = 20, y = 60. So the garden should be 20 ft by 60 ft.
Answer:
Length of the field: 94 m
Width of the painting: 61 cm
Step-by-step explanation:
Use the perimeter formula, P = 2l + 2w, to find the length:
Plug in the perimeter and width into the equation:
P = 2l + 2w
336 = 2l + 2(74)
336 = 2l + 148
188 = 2l
94 = l
So, the length of the field is 94 m.
To find the width of the painting, use the area formula, A = lw
Plug in the area and length into the equation:
A = lw
5795 = 95w
61 = w
So, the width of the painting is 61 cm.
Length of the field: 94 m
Width of the painting: 61 cm
Answer:
27.5 mm
Step-by-step explanation:
The game piece has the shape of two identical square pyramids attached at their bases. Given that the perimeters of the square bases are 80 millimeters, and the slant height of each pyramid is 17 millimeters.
Let the side length of each of the side of the base of the pyramid be b, hence:
perimeter = 4b
80 = 4b
b = 20 mm. half of the side length = b/2 = 20 / 2 = 10 mm
The slant height (l) = 17 mm, Let h be the height of one of the pyramid, hence, using Pythagoras theorem:
(b/2)² + h² = l²
17² = 10² + h²
h² = 17² - 10² = 189
h = √189
h = 13.75 mm
The length of the game piece = 2 * h = 2 * 13.75 = 27.5 mm.
Answer:
End fraction right brace
Step-by-step explanation:
I really hope I helped GL <33!
