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3 years ago

What is the value for x? Enter your answer in the box. X=

Mathematics

2 answers:

Mice21 [21]3 years ago

6 0

this is an isoscele triangle, AB = BC, and the angle A is equal angle C.

8y - 7 = 73

8y = 73 + 7

8y = 80

y = 80 : 8

y = 10

------------------------

the sum of the interior angles is 180°

180 - 73 - 73 = 34° (angle B)

6x + 4 = 34

6x = 30

x = 30 : 6 =

x = 5

irakobra [83]3 years ago

3 0

since this is an isosceles triangle, angle a =angle c

73 = 8y-7

add 7 to each side

80 = 8y

divide by 8

y =10

the sum of all three angles =180

<a +<b+<c = 180

73+6x+4 +73 = 180

add like terms

150 +6x = 180

subtract 150 from each side

6x = 30

divide by 6

x=5

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You're conducting a significance test for H0 : p = .35, Ha : p < .35. In a sample of size 40, you identify a count of 11 succ

nordsb [41]

Answer: c. –1 and .1587

Step-by-step explanation:

As per given , we have

Null hypothesis : $H_0 : p= 0.35$

Alternative hypothesis : $H_1 : p< 0.35$

Since Alternative hypothesis is left-tailed ,so the test must be a left tailed test .

Z -Test statistic for proportion = $z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}$

, where p= population proportion

$\hat{p}$ = sample proportions

n= Sample size.

Let x be the number of successes.

For n= 40 and x= 11

$\hat{p}=\dfrac{x}{n}=\dfrac{11}{40}=0.275$

Then , $z=\dfrac{0.275-0.35}{\sqrt{\dfrac{0.35(1-0.35)}{40}}}$

$z=\dfrac{-0.075}{\sqrt{0.0056875}}$

$z=\dfrac{-0.075}{0.075415515645}$

$z=-0.99449031619\approx-1$

By using z-table ,

P-value for left-tailed test = P(z<-1)= 1-P(z<1) [∵ P(Z<-z)= 1-P(Z<z) ]

= 1-0.8413

=0.1587

Hence, the -score and P-value are <u>–1 and 0.1587</u> .

So the correct option is c. –1 and .1587

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rosijanka [135]

Answer:

Step-by-step explanation:

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Ira Lisetskai [31]

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Karo-lina-s [1.5K]

$\text{The scientific notation:}\\\\a\times10^n\\\\1\leq a$

$a.\\(5\times10^3)\times(3.5\times10^{-1})=(5\times3.5)\times(10^3\times10^{-1})\\\\=15.75\times10^{3+(-1)}=15.75\times10^2=1.575\times10\times10^2\\\\=1.575\times10^{1+2}=\boxed{1.575\times10^3}$

$b.\\(8\times10^2)\div(4\times10^3)=(8\div4)\times(10^2\div10^3)=2\times10^{2-3}\\\\=\boxed{2\times10^{-1}}$

$c.\\(6\times10^{-3})^2=6^2\times(10^{-3})^2=36\times10^{-3\cdot2}=36\times10^{-6}=3.6\times10\times10^{-6}\\\\=3.6\times10^{1+(-6)}=\boxed{3.6\times10^{-5}}$

$Used:\\\\a^n\times a^m=a^{n+m}\\\\a^n\div a^m=a^{n-m}\\\\(a^n)^m=a^{n\cdot m}$

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nordsb [41]

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