What does simplifying the ratio of am to 250 mm to 50 cm give?

Let t[1..n] be a sorted array of distinct integers, some of which may be negative. give an algorithm that can find an index i su

lisabon 2012 [21]

Assuming we need to find i such that
1 ≤ i ≤ n and t[i]=i.

If we need to find only the first occurrence, we can do:

for i:1 to n {
if t[i]=i then return(i)
}

If exhaustive search is required, then put the results (values of i) in an array or a linked list, return the number of values found, and the array (or linked list).

8 0

3 years ago

A café owner is designing a new menu and wants to include a decorative border around the outside of her food listings. Due to th

Zielflug [23.3K]

Answer:

Step-by-step explanation.

6 0

2 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago

Combine like terms in the expression below:<br> 9x + 4.05xy + 15y + 30y - 11x + 9.46

aev [14]

Answer: 4.05 x y − 2 x + 45 y + 9.46

Step-by-step explanation:

9x + 4.05xy + 15y + 30y - 11x + 9.46

4.05xy + 9x - 11x + 15y+ 30y+ 9.46

4.05 x y − 2 x + 45 y + 9.46

6 0

3 years ago

Robert bought his car 4 years ago.

Anni [7]

If i'm correct. it should be $10,022.40

3 0

3 years ago

What does simplifying the ratio of am to 250 mm to 50 cm give?​

What does simplifying the ratio of am to 250 mm to 50 cm give?