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3 years ago

12

Please be quickly I beg you

1 answer:

OverLord2011 [107]3 years ago

3 0

The shape is a rectangle, i’m not familiar with the other problem though sorry :/

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Explain how the segment addition postulate can be modeled using a real-world object.

Semmy [17]

To determine the length of AB, one must subtract BC from AC. If the length of AC is 18 and the length of BC is 4, then using this formula yields 18 - 4 = 14, so the length of AB is 14.This postulate also allows a line segment that has only two known points to be broken into two line segments with the addition of a third point in between the endpoints. This is useful for proofs in geometry and analysis.

brainly.com/question/1721582

8 0

4 years ago

Nicholas is buying shirts for his baseball team. He will pay $9.50 for each shirt plus a

sladkih [1.3K]

Answer:

A

Step-by-step explanation:

cause x shirts times 9.5(the price of shirt)+ one time fee

6 0

3 years ago

Consider a roulette wheel consisting of 38 numbers 1 through 36, 0, and double 0. If Smith always bets that the outcome will be

Step2247 [10]

Answer:

The probability that Smith will lose his first 5 bets is 0.15

The probability that his first win will occur on his fourth bet is 0.1012

Step-by-step explanation:

Consider the provided information.

A roulette wheel consisting of 38 numbers 1 through 36, 0, and double 0. Smith always bets that the outcome will be one of the numbers 1 through 12,

It is given that Smith always bets on the numbers 1 through 12.

There are 12 numbers from 1 to 12.

Thus, the probability of success (winning) is= $\frac{12}{38}$

The probability of not success (loses) is= $1-\frac{12}{38}=\frac{26}{38}$

Part (A) Smith will lose his first 5 bets.

The probability that Smith loses his first 5 bets is,

$\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}=(\frac{26}{38})^5\approx0.15$

Hence, the probability that Smith will lose his first 5 bets is 0.15

Part (B) His first win will occur on his fourth bet?

Smith’s first win occurring on the fourth bet means that he loses the first 3 bets and wins on the fourth bet. That is,

$\frac{26}{38}\times\frac{26}{38}\times\frac{26}{38}\times\frac{12}{38}=(\frac{26}{38})^3\times\frac{12}{38}\approx0.1012$

Hence, the probability that his first win will occur on his fourth bet is 0.1012

6 0

3 years ago

Luca baked 18 dozen chocolate chip cookie dozen peanut butter cookie how many cookie did Luca bake

Katen [24]

Answer:

he baked 216 cookies

Step-by-step explanation:

the equation for this is 18x12 since for every one dozen there are 18 cookies

7 0

2 years ago

Help pleaseeeee!!!!!!!

lorasvet [3.4K]

okay I will help what is it

5 0

3 years ago