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3 years ago

9.173 what is the value of 9?

Mathematics

2 answers:

SashulF [63]3 years ago

8 0

Answer:

Step-by-step explanation:

omeli [17]3 years ago

3 0

Answer:

the value of 9 is ones

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Please help thank you very much

mezya [45]

1. 22
2.34
3. first one
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3 years ago

Q # 19 The data below shows the. number of hours a week on average group of students spend volunteering for community service pr

alisha [4.7K]

If those two are your only choices then the answer is none of the above.

<em>Attached is a cumulative frequency table for your data.</em>

If you take a look at the two tables given, the frequencies were not tallied properly. If the frequency column is wrong, then the cumulative frequency will be wrong.

The answer is then none of the above or find one that matches the table attached.

7 0

3 years ago

Which number line represents the solutions to 1-2x1 = 4?

kaheart [24]

Answer:

Third option: $x = -2$ and $x = 2$

Step-by-step explanation:

Given:

$|-2x|=4$

For a modulus function, if $|f(x)|=a$ , then,

$f(x)=\pm a$

Here, $f(x)=-2x$ , $a=4$

∴ $-2x=\pm 4\\ -2x=-4\textrm{ or } -2x=4\\ x=\frac{-4}{-2}\textrm{ or }x=\frac{4}{-2}\\ x= 2\textrm{ or }x=-2$

Therefore, the third option is the correct answer as the graph has $x$ values as -2 and 2

8 0

3 years ago

Find the line through (3, 1, −2) that intersects and is perpendicular to the line x = −1 + t, y = −2 + t, z = −1 + t. (HINT: If

mel-nik [20]

Answer:

( xo , yo , zo ) = ( 1 , 0 , 1 )

Step-by-step explanation:

Given:-

- A line passing through point (3, 1, −2) intersects and is perpendicular to line with coordinates:

x = −1 + t, y = −2 + t, z = −1 + t .... t = arbitrary parameter.

Find:-

The coordinates for point of intersection.

Solution:-

- The line that passes through point (3, 1, −2) = ( a, b , c ) and an a arbitrary point on the given line have the following direction vector d2 :

d2 = ( x2 , y2 , z2 )

x2 = a - ( x ) = 3 - ( -1 + t ) = 4 - t

y2 = b - ( y ) = 1 - ( -2 + t ) = 3 - t

z2 = c - ( z ) = -2 - ( -1 + t ) = -1 - t

d2 = ( 4 - t , 3 - t , -1 - t )

- The direction vector d1 of the given line is:

d1 = ( x1 , y1 , z1 )

x1 = 1

y1 = 1

z1 = 1

d1 = ( 1 , 1 , 1 )

- The dot product of two orthogonal vectors is always equal to zero:

d1.d2 = 0

( 4 - t , 3 - t , -1 - t ) . ( 1 , 1 , 1 ) = 0

- Solve for parameter (t):

(4 - t) + (3 - t) + (-1 - t) = 0

6 -3t = 0

t = 2

- The coordinates of the point of intersections can be evaluated by substituting the value of "t" into the given equation of line:

xo ( t = 2) = - 1 + 2 = 1

yo ( t = 2) = - 2 + 2 = 0

zo ( t = 2) = - 1 + 2 = 1

- The coordinates are:

( xo , yo , zo ) = ( 1 , 0 , 1 )

8 0

3 years ago

Someone plz answer i rlly need help Solve for a.<br><br> a+(−1.6)=−3.7

Norma-Jean [14]

Hi there!

All you need to do to solve for a is add 1.6 to both sides of the equation.

It will look like this:
a - 1.6 + 1.6 = -3.7 + 1.6

After this you will see that a = -2.1.

Hope this helps!
When in doubt just replace a with -2.1 and see if you still get -3.7. :)

3 0

3 years ago

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