Not enough information- the coupon will only be worth 24% after tax though.
Answer:
san po jan
<h3>step_by istep explanation_</h3>
a.
The polynomial w^2+18w+84 cannot be factored
The perfect square trinomial is w^2+18w + 81
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The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.
w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9
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b.
The polynomial y^2-10y+23 cannot be factored
The perfect square trinomial is y^2-10y + 25
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Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.
If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)
Apply to Row 2 : Row 2 + Row 1
2x + 2y + 3z = 0
y + 4z = -3
2x + 3y + 3z = 5
Apply to Row 3: Row 3 - Row 1
2x + 2y + 3z = 0
y + 4z = -3
y = 5
Apply to Row 3: Row 3 - Row 2
2x + 2y + 3z = 0
y + 4z = -3
-4z = 8
Simplify rows
2x + 2y + 3z = 0
y + 4z = -3
z = -2
<em>Note that the matrix is in echelon form now. The next steps are for back substitution.</em>
Apply to Row 2: Row 2 - 4 Row 3
2x + 2y + 3z = 0
y = 5
z = -2
Apply to Row 1: Row 1 - 3 Row 3
2x + 2y = 6
y = 5
z = -2
Apply to Row 1: Row 1 - 2 Row 2
2x = -4
y = 5
z = 2
Simplify the rows
<u>x = -2</u>
<u>y = 5</u>
<u>z = -2</u>
I think it = 16 but then again I could be wrong