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3 years ago

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0.0354 Scientific Notation Need Answers Quick

1 answer:

Crank3 years ago

5 0

3.54 • 10*-2

Step-by-Step Solution:

Place the decimal point after the first non-zero number, and multiply by 10 to the appropriate power I.e., how many places you would need to move the decimal to get the original number.

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1.) The commuter trains on the Red Line for the Regional Transit Authority (RTA) in Cleveland, OH, have a waiting time during pe

alisha [4.7K]

Answer:

a) For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

$X \sim Unif(a=0,b=8)$

Where a and b represent the limits of the distribution.

b) $f(x) = \frac{1}{8}= 0.125, a\leq x \leq b$

And the height for this case would be 0.125

Step-by-step explanation:

Part a

For this case we define the random variable as X ="waiting time during peak hours" and we know that this distribution follows an uniform distribution:

$X \sim Unif(a=0,b=8)$

Where a and b represent the limits of the distribution.

Part b

For this case the density function would be given by:

$f(x) = \frac{1}{8}= 0.125, a\leq x \leq b$

And the height for this case would be 0.125

And $f(x)= 0$ for other case.

The cumulative distribution function would be given by:

$F(x) = 0, x$

$F(x) = \frac{x-a}{b-a}= \frac{x}{8}, 0\leq x < 8$

$F(x) = 1, x\geq 8$

3 0

2 years ago

15/2 as a decimal plz first person to answer is going to be the brainleist

I am Lyosha [343]

Its 17.5 im 100% sure

3 0

3 years ago

Read 2 more answers

Find a positive number for which the sum of it and its reciprocal is the smallest (least) possible. Let x be the number and let

Allisa [31]

Answer:

$S(x) = x + \frac{1}{x}$ --- Objective function

Interval = $\{x:x=1\}$

Step-by-step explanation:

Given

Represent the number with x

The required sum can be represented as:

$x + \frac{1}{x}$

Hence, the objective function is:

$S(x) = x + \frac{1}{x}$

To get the the interval, we start by differentiating w.r.t x

<em>Using first principle, this gives:</em>

$S'(x) = 1 - \frac{1}{x^2}$

Equate S'(x) to 0 in order to solve for x

$0 = 1 - \frac{1}{x^2}$

Subtract 1 from both sides

$0 -1 = 1 -1 - \frac{1}{x^2}$

$-1 = - \frac{1}{x^2}$

Multiply both sides by -1

$1 = \frac{1}{x^2}$

Cross Multiply

$x^2 * 1 = 1$

$x^2 = 1$

Take positive square root of both sides because x is positive

$\sqrt{x^2} = \sqrt{1$

$x = 1$

Representing x using interval notation, we have

Interval = $\{x:x=1\}$

To get the smallest sum, we substitute 1 for x in $S(x) = x + \frac{1}{x}$

$S(1) = 1 + \frac{1}{1}$

$S(1) = 1 + 1$

$S(1) = 2$

<em>Hence, the smallest sum is 2</em>

3 0

3 years ago

What are factors of 42 that subtract to -8

MrRa [10]

You might have to do the quadratic formula

8 0

3 years ago

What is the value of n in the equation 1/2 (n-4)-3=3-(2n+3)?

patriot [66]

Answer:

Solve for

n

by simplifying both sides of the equation, then isolating the variable.

n

=

2

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers