Question

PLEASE HELP ME ASAP!!!! My entire grade depends on these questions and I need to show the work that go me there

Answer 1

Answer:

Answers are in bold

Step-by-step explanation:

Part 1A

Use the Zero Product Property to find the x-intercepts:

0=-(x+4)(x-1)

0=(x+4)(x-1)

0=(x+4)

-4=x

x=-4

0=(x-1)

1=x

x=1

So the x-intercepts are x=-4 and x=1 which is also (-4,0) and (1,0)

For the y-intercepts, plug in x=0:

f(x)=-(0+4)(0-1)

f(x)=(-4)(-1)

f(x)=4

So the y-intercept is y=4 which is also (0,4)

Part 1B

In general, the axis of symmetry is equal to x=h in the equation y=(x-h)^2+k

For a parabola, the axis of symmetry is equal to x=-b/2a, so we expand the given equation and then plug in the values of "a" and "b" to get the axis of symmetry:

f(x)=-(x+4)(x-1)

f(x)=-(x^2+3x-4)

f(x)=-x^2-3x+4

So now we know a=-1 and b=-3, therefore we can plug them in:

x=-b/2a

x=-(-3)/2(-1)

x=3/-2

x=-3/2

x=-1.5

So the equation of the axis of symmetry is x=-1.5

Part 1C

We'll use the equation x=-b/2a to get the x-coordinate for the vertex (which we already know is x=-1.5), then plug in that value of x in the original equation to get the y-coordinate for the vertex:

f(x)=-(-1.5+4)(-1.5+1)

f(x)=-(2.5)(-0.5)

f(x)=-(-1.25)

f(x)=1.25 <-- y-coordinate

So the coordinates of the vertex are (-1.5,1.25)

Part 1D

See the image below

I'll let someone else do the last 4 questions as I am unable to answer them.