Part A: Describe in words how you can find the rate of change of a bushel of corn in the current year, and find the value.

A daily mail is delivered to your house between 1:00 p.m. and 5:00 p.m. Assume delivery times follow the continuous uniform dist

german

Answer:

25% of deliveries

Step-by-step explanation:

This is a uniform distribution with parameters a = 1.00 and b =5.00. With these conditions, the following probability distribution functions can be applied:

$P(X \leq x)=\frac{x-a}{b-a}=\frac{x-1.00}{5.00-1.00}\\P(X \leq x) = \frac{x-1}{4}\\P(X \geq x) = 1- P(X \leq x) \\P(X \geq x)=1- \frac{x-1}{4}$

Therefore, the probability that X ≥ 4:00 p.m. is given by

$P(X \geq 4)=1- \frac{4-1}{4}\\P(X \geq 4)=0.25=25\%$

Thus, 25% of deliveries are made after 4:00 p/m.

7 0

3 years ago

Need help please !!!

irina1246 [14]

sin^2 x + 4 sinx +3 3 + sinx

-------------------------- = -------------------

cos^2 x 1 - sinx

factor the numerator

(sinx +3) (sinx+1) 3 + sinx

-------------------------- = -------------------

cos^2 x 1 - sinx

cos^2 = 1-sin^2x

(sinx +3) (sinx+1) 3 + sinx

-------------------------- = -------------------

1- sin^2x 1 - sinx

factor the denominator

(sinx +3) (sinx+1) 3 + sinx

-------------------------- = -------------------

(1-sinx ) (1+sinx) 1 - sinx

cancel the common term (1+sinx) and (sinx +1)

(sinx +3) 3 + sinx

-------------------------- = -------------------

(1-sinx ) 1 - sinx

reorder the first term

3+sinx 3 + sinx

-------------------------- = -------------------

(1-sinx ) 1 - sinx

3 0

3 years ago

Angle A and angle B are supplementary angles. If m angle A = (5x+2) and m angle B = (8x+9) , then find the measure of angle B

otez555 [7]

You first identify what supplementary angles are,angles that add up to 180.
5x+2+8x+9=180
17x+11=180-11
17x=169
x=169divided by 17
x=9.9411
x=10 when rounded into the next value
8x*10=80+989

8 0

3 years ago

Suppose the weights of the Boxers at this club are Normally distributed with a mean of 166 pounds and a standard deviation of 5.

lesya [120]

Answer:

0.1994 is the required probability.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 166 pounds

Standard Deviation, σ = 5.3 pounds

Sample size, n = 20

We are given that the distribution of weights is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{5.3}{\sqrt{20}} = 1.1851$

P(sample of 20 boxers is more than 167 pounds)

$P( x > 167) = P( z > \displaystyle\frac{167 - 166}{1.1851}) = P(z > 0.8438)$

$= 1 - P(z \leq 0.8438)$

Calculation the value from standard normal z table, we have,

$P(x > 167) = 1 - 0.8006= 0.1994 = 19.94\%$

0.1994 is the probability that the mean weight of a random sample of 20 boxers is more than 167 pounds

3 0

3 years ago

Find the 6th term of a geometric sequence with t1=5 and r = -1/2

Hoochie [10]

In this item, we are to calculated for the 6th term of the geometric sequence given the initial value and the common ratio. This can be calculated through the equation,

An = (A₀)(r)ⁿ ⁻ ¹
where An is the nth term, A₀ is the first term (in this item is referred to as t₀), r is the common ratio, and n is the number of terms.

Substitute the known values to the equation,

An = (5)(-1/2)⁶ ⁻ ¹
An = -5/32

Hence, the answer to this item is the third choice, -5/32.

5 0

3 years ago