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2 years ago

The radius of a circle is 19 km what is the circles area using 3.14 for pie

Mathematics

2 answers:

Sholpan [36]2 years ago

5 0

Answer:

1133.54 or 361 pi

Step-by-step explanation:

19^2*pi

Butoxors [25]2 years ago

4 0

Answer: 1133.54

Step-by-step explanation:

The formula to find the area of a circle is $\pi$ times the radius squared. The radius here is 19 so in order to square 19 you have to do 19x19 which is 361. Then, just multiply 361 by 3.14 and you should get 1133.54 as your final answer. Hope this helps!

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How many gallons of a 50% antifreeze solution must be mixed with 60 gallons of 30% antifreeze to get a mixture that is 40% antif

Mariulka [41]

I don't know what the "six-step method" is supposed to be, so I'll just demonstrate the typical method for this problem.

Let x be the amount (in gal) of the 50% antifreeze solution that is required. The new solution will then have a total volume of (x + 60) gal.

Each gal of the 50% solution used contributes 0.5 gal of antifreeze. Similarly, each gal of the 30% solution contributes 0.3 gal of antifreeze. So the new solution will contain (0.5 x + 0.3 * 60) gal = (0.5 x + 18) gal of antifreeze.

We want the concentration of antifreeze to be 40% in the new solution, so we need to have

(0.5 x + 18) / (x + 60) = 0.4

Solve for x :

0.5 x + 18 = 0.4 (x + 60)

0.5 x + 18 = 0.4 x + 24

0.5 x - 0.4 x = 24 - 18

0.1 x = 6

x = 6/0.1 = 60 gal

6 0

3 years ago

Jessica wrote down a fraction on a piece of paper. If you take her fraction and multiply it by four you get sex. can you guess w

RideAnS [48]

1 1/2

6÷4 = 1 1/2

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6 0

3 years ago

ACTIVITY 2 (19) Mr Duma recently inherited a rectangular plot, part of the estate left by his late father. The plot with the fol

seraphim [82]

The sum of the lengths of three sides of the rectangle, gives the length

of the fencing, while one third of the rectangle area is for the pavement.

Responses:

Project A: The formula for the length of the fencing is, L = 4·x - 1

Project B: Length of the fancy wall = 2·x + 1

$Project \ C:Area \ of \ the \ paving = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3} - \dfrac{1}{3}}$

<h3>Which method can be used to find the length and area of paving from the given equations?</h3>

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Given parameters are;

Length of the rectangular plot = 2·x + 1

Width of the rectangular plot = x - 1

Vertices of the rectangular plot are; QPSR

Project A: Let QP and SR represent the longest sides of the rectangle, we have;

PQ = SR = 2·x + 1

Which gives;

SP = QR = x - 1

The length of the fencing, L = SP + PQ + QR = x - 1 + 2·x + 1 + x - 1 = 4·x - 1

The formula for the length of the fencing is, L = 4·x - 1

Project B: The front side is SR

Therefore;

Length of the fancy wall = 2·x + 1

Project C:

Area, A = Length × Width

Area of the plot, A = (2·x + 1) × (x - 1) = 2·x² - x - 1

$Area \ of \ the \ paving = \dfrac{1}{3} \times \left(2 \cdot x^2 - x - 1\right) = \underline{ \dfrac{2\cdot x^2 }{3} - \dfrac{x }{3} - \dfrac{1}{3}}$

Learn more about writing equations here:

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6 0

2 years ago

The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(

forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

Considering that $P(BIA)= \frac{P(AnB)}{P(A)}$ you can clear the intersection from the formula $P(AnB)= P(B/A)*P(A)$ and apply it for the given events: