For what problem
Answer pls
Answer:
Given
Number of stacks = 2
Stack 1 = 6 cups; h1 = 15cm
Stack 2 = 12 cups; h2 = 23cm
Let's first find the average:
With an average of 4/3, to obtain the number of cups needed to obtain a height of 50m, we have:
50 / (4/3)
= 50 * 3/4
= 150/4
= 37.5
From the answer, we can see that the number of cups is not really proportional to the height of the stack, because the average of stack one and stack 2 are different.
Step-by-step explanation:
15 - 9 + 2.65 + 1.35 + 3.48
6 + 2.65 + 1.35 + 3.48
8.65 + 1.35 + 3.48
10 + 3.48
13.48
The question did not spesify the stating value for n.
Assuming, n = 0 is the starting value.
1st term is when n = 0:
f(0) = (0)^2 - 5 = 0 - 5 = -5
2nd term: f(1) = (1)^2 - 5 = 1 - 5 = -4
3rd term: f(2) = (2)^2 - 5 = 4 - 5 = -1
4th term: f(3) = (3)^2 - 5 = 9 - 5 = 4
Therefore, the first 4 terms are: -5, -4, -1, 4.
Answer:
the probability that the shipment is accepted is 0.8865
Step-by-step explanation:
Given the data in the question;
N = 86, n/d = 5 and n = 2
now, without replacement
the probability that the shipment is accepted will be;
probability that the shipment is accepted = probability that non is defectives
so p( non is defective ) = ( (86-5)/86) × ((86-5-1)/(86-1))
p( non is defective ) = ( 81 / 86) × (80/85)
p( non is defective ) = 0.8865
Therefore, the probability that the shipment is accepted is 0.8865
