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3 years ago

Write an equation that passes through the points (3, 6) and (1,-1)

2 answers:

7 0

Finding gradient:

m = y2 - y1
x2 - x1

= -1 - 6
1 - 3

= -7 / (-2)
= 7/2

y = m(x - x1) + y1
y = 7(x - 3) + 6
2
2y = 7x - 21 + 12
2y = 7x - 9

Lady bird [3.3K]3 years ago

7 0

Answer:

y = 7/2x - 9/2

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - 6 / 1 - 3

-7 / -2

7/2

y = 7/2x + b

-1 = 7/2(1) + b

-1 = 7/2 + b

-9/2 = b

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Suppose you have a bag containing 2 black marbles and 3 red marbles. You reach into the bag, select a marble, see what color it

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Answer:

$\dfrac{9}{25}$

Step-by-step explanation:

Given that the bag contains black and red marbles.

Number of black marbles in the bag = 2

Number of red marbles in the bag = 3

Total number of marbles in the bag = Number of black marbles + Number of red marbles = 2 + 3 = 5

Let us have a look at the formula for probability of an event E, which can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(\text{First red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5 }$

Now, the marble chosen at first is replaced.

Therefore, the count remains the same.

$P(\text{Second red marble}) = \dfrac{\text{Number of red marbles}}{\text{Total number of marbles}} = \dfrac{3}{5}$

Now, the <em>required probability</em> can be found as:

$P(\text{First red marble})\times P(\text{Second red marble}) = \dfrac{3}{5}\times \dfrac{3}{5} = \bold{\dfrac{9}{25} }$

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3 years ago

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Answer:

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