Where’s point P at though
Answer:
Yes.
Step-by-step explanation:
Yes, because we can replace x^3 by another variable, say y:
x^9 - 5x^3 + 6 = 0
Let x^3 = y, then we have x^9 = (x^3)^2 = y^2:
y^2 - 5y + 6 = 0 which is quadratic from.
Answer:
x= - 36
Step-by-step explanation:
Answer:
6
Step-by-step explanation:
a=V⅓=216⅓=6
hope this helped