All categories

2 years ago

Write an equation that passes through the points (3, 6) and (1,-1)

2 answers:

7 0

Finding gradient:

m = y2 - y1
x2 - x1

= -1 - 6
1 - 3

= -7 / (-2)
= 7/2

y = m(x - x1) + y1
y = 7(x - 3) + 6
2
2y = 7x - 21 + 12
2y = 7x - 9

Lady bird [3.3K]2 years ago

7 0

Answer:

y = 7/2x - 9/2

Step-by-step explanation:

y2 - y1 / x2 - x1

-1 - 6 / 1 - 3

-7 / -2

7/2

y = 7/2x + b

-1 = 7/2(1) + b

-1 = 7/2 + b

-9/2 = b

You might be interested in

The perimeter of a certain rectangle is 16 times the width. The length is 12 cm more than the width. Find the length and width o

Blizzard [7]

Check the picture below

surely you know how much that is.

8 0

3 years ago

In art class mrsJocelyn gave everyone a 1 foot stick to measure and cut Vivian measured and cut her stick into 5 equal pieces Sc

garri49 [273]

Idk sorry i cant help

hope this helps XD

6 0

3 years ago

2. Solve each given equation and show your work. Tell whether it has one solution, an infinite number of

marin [14]

Answer:

a. infinite solutions, answer is x = 30, identity equation

b. no solution, a contradiction equation

c. no solution, a contradiction equation

Step-by-step explanation:

3 0

2 years ago

Monica deposits $100 into a savings account that pays a simple interest rate of 3.8%. Paul

Gnom [1K]

Answer:

Paul

Step-by-step explanation:

Paul earn more than monica. Though he is getting less interest but because of his higher initial amount he is getting more return.

Computing the return of both

Monica return is 100*3.4%= $3.4 in a year

Paul return is 200*%2.2= $4.4 in a year.

7 0

2 years ago

Read 2 more answers

Assuming that the equations define x and y implicitly as differentiable functions x=f(t),y=g(t) find the slope of the curve x=f(

Mumz [18]

The given equations are
$x(t+1)-4t \sqrt{x} =9$ (1)
$2y+4y^{3/2}=t^{3}+t$ (2)

When t=0, obtain
$x=9 \\ 2y+4y^{3/2}=0 \,\,=\ \textgreater \ \, y(1+2 \sqrt{y} )=0 \,=\ \textgreater \ \,y=0$

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means $\frac{dx}{dt}$ .

Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means $\frac{dy}{dt}$ .

Because $\frac{dy}{dx} = \frac{dy}{dt} / \frac{dx}{dt}$ , obtain
$\frac{dy}{dx} |_{t=0}\, = \frac{1/2}{3}= \frac{1}{6}$

Answer:
The slope of the curve at t=0 is 1/6.

3 0

3 years ago