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Svetllana [295]
3 years ago
12

Solve for x: 2x/5=12/8

Mathematics
2 answers:
Anika [276]3 years ago
5 0

Answer:

x = 3\frac{3}{4}

Step-by-step explanation:

First, you have to leave 2x by itself on the left side of the equation:

2x = 60/8

Then divide,

x = 15/4

Simplified fraction: x = 3\frac{3}{4}

Ksenya-84 [330]3 years ago
4 0

Answer:

exact form: x=15/4

decimal form; 3.75

miced number: 3  3/4

Step-by-step explanation:

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Step-by-step explanation:

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Stella [2.4K]

Answer:

The 95% confidence interval would be given by -23.44 \leq \mu_1 -\mu_2 \leq -8.16  

Step-by-step explanation:

Previous concepts  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

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\bar X_1 =114.1 represent the sample mean 1

\bar X_2 =129.9 represent the sample mean 2

n1=5 represent the sample 1 size  

n2=2 represent the sample 2 size  

s_1 =5.08 sample standard deviation for sample 1

s_2 =5.37 sample standard deviation for sample 2

\mu_1 -\mu_2 parameter of interest.

Confidence interval

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm t_{\alpha/2}\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}} (1)  

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\bar X_1 -\bar X_2 =114.1-129.9=-15.8

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:  

df=n_1 +n_2 -1=5+5-2=8  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,8)".And we see that t_{\alpha/2}=\pm 2.31  

The standard error is given by the following formula:

SE=\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}

And replacing we have:

SE=\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=3.306

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Now we have everything in order to replace into formula (1):  

-15.8-2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-23.437  

-15.8+2.31\sqrt{\frac{5.08^2}{5}+\frac{5.37^2}{5}}=-8.163  

So on this case the 95% confidence interval would be given by -23.44 \leq \mu_1 -\mu_2 \leq -8.16  

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Answer:

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