Answer:
Step-by-step explain
Find the horizontal asymptote for f(x)=(3x^2-1)/(2x-1) :
A rational function will have a horizontal asymptote of y=0 if the degree of the numerator is less than the degree of the denominator. It will have a horizontal asymptote of y=a_n/b_n if the degree of the numerator is the same as the degree of the denominator (where a_n,b_n are the leading coefficients of the numerator and denominator respectively when both are in standard form.)
If a rational function has a numerator of greater degree than the denominator, there will be no horizontal asymptote. However, if the degrees are 1 apart, there will be an oblique (slant) asymptote.
For the given function, there is no horizontal asymptote.
We can find the slant asymptote by using long division:
(3x^2-1)/(2x-1)=(2x-1)(3/2x+3/4-(1/4)/(2x-1))
The slant asymptote is y=3/2x+3/4
Answer:
Since 4 is the largest number its the hypotenuse. The two 3s are equal so they are interchangeable so it doesn't matter where you put them. If its a right triangle the hypotenuse is opposite the right angle.
Step-by-step explanation:
Your answer would be 24 and 168
take the 48 and divide by 4 to get the 1st one then just multiply 24 by 7 and you get 168
Answer:
x² + 4x + 3
Step-by-step explanation:
to find f(g(x)), substitute x = g(x) into f(x)
f(g(x)) = f(x + 2) = (x + 2)² - 1 = x² + 4x + 4 - 1 = x² + 4x + 3
Answer:
Step-by-step explanation:
four twelfths minus two twelfths equals two twelfths
