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Mumz [18]
2 years ago
12

Please help me with this its due in 15 minutes plus ill need help with more

Mathematics
1 answer:
Anestetic [448]2 years ago
3 0

Answer:

171 Square Feet

Step-by-step explanation:

We first cut the figure up into smaller parts...

we then use the formula (L x W = A) to find the area

L = Lenth

W = Width

the first rectangle (1)...

15 x 5 = 75

the second figure (2)...

8 x 9 = 72

the third figure (3)...

6 x 4 = 24

now we have to add up all the values to find the area of the entire figure...

75 + 72 + 24 = 171

<em>Hope this helps! Please let me know if you need more help or think my answer is incorrect. Brainliest would be MUCH appreciated. Also remember to rate answers to help other students, While leaving thanks to answers that help you. Have a great day!</em>

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Answer:

17

Step-by-step explanation:

170/10=17

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3. A prop for the theater club’s play is constructed as a cone topped with a half-sphere. What is the volume of the prop? Round
Tanzania [10]
1. To solve this problem you must sum the volume of the cone and the volume of the hemisphere. This means that the volumen of the prop is:

 Vt=Vc+Vh

 Vt is the volumen of the prop.
 Vc is the volumen of the cone.
 Vh is the volume of the hemisphere.

2. The volume of the cone (Vc) is:

 Vc=1/3(πr²h)

 r=9 in
 h=14 in
 π=3.14

 4. Then, you have:

 Vc=(3.14)(9 in)²(14 in)/3
 Vc=3560.76 in³/3
 Vc=1186.92

 5. The volume of the hemisphere (Vh) is:

 Vh=2/3(πr³)

 π=3.14
 r=9 in

 6. Then, you have:

 Vh=(2)(3.14)(9 in)³/3
 Vh=4578.12 in³/3
 Vh=1526.04 in³

 7. Finally, the volumen of the prop (Vt) is:

 Vt=Vc+Vh
 Vt=1186.92 in³+1526.04 in³
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<span>
 What is the volume of the prop?
</span>
 The volume of the prop is 2713.0 in³
6 0
4 years ago
Find a 90% confidence interval for the mean of all tree ring dates from this archaeological site. (round your answers to the nea
creativ13 [48]
Given a table below which gives the years in A.D. for an archaeological excavation site using the method of tree ring dating:

\begin{tabular}&#10;{|c|c|c|c|c|c|c|c|c|}&#10;1229&1292&1187&1257&1268&1316&1275& 1317&1275&#10;\end{tabular}

Part A:

The sample mean is given by:

\bar{x}= \frac{1229+1292+1187+1257+1268+1316+1275+ 1317+1275}{9} \\  \\  = \frac{11416}{9} =1268

Therefore, the sample mean is 1268.



Part B:

We calculate the sample standard deviation as follows:

s= \frac{1}{9-1} \left(\sqrt{(1229-1268)^2+(1292-1268)^2+(1187-1268)^2+(1257-1268)^2+(1268-1268)^2+(1316-1268)^2+(1275-1268)^2+(1317-1268)^2+(1275-1268)^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{(-39)^2+24^2+(-81)^2+(-11)^2+0^2+48^2+7^2+49^2+7^2}\right)\\ \\ = \frac{1}{8}\left(\sqrt{1521+576+6561+121+2304+49+2401+49}\right)\\ \\ = \frac{1}{8}\left(\sqrt{13,582}\right)\\ \\ = \frac{1}{8}(116.54)=14.57\approx15



Part C:

The 90% confidence interval is given by:

90\% \ C. \ I.=1268\pm1.65\left(\frac{15}{\sqrt{9}}\right) \\  \\ =1268\pm\left(\frac{15}{3}\right)=1268\pm5 \\  \\ =(1268-5, \ 1268+5)=(1263, \ 1273)
8 0
3 years ago
8^p^3=?<br> Simplify the expression.
Ratling [72]
Its 8p3.....................
8 0
3 years ago
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