1 penny is just 1c
one nickel is 5 pennies or 5c
alrite...
p = amount of pennies in the jar
n = amount of nickels in the jar
we know there are 56 coins in the jar, thus whatever "p" and "n" are,
p + n = 56
we also know, the total value of all pennies and nickels is one buck and 52 cents, or 1.52.. that's 152 pennies.
now, we know there are 5 pennies in one nickel, so in "n" nickels, there are 5*n pennies, or 5n, thus
p + 5n = 152
![\bf \begin{cases} p+n=56\implies \boxed{n}=56-p\\ p+5n=152\\ ----------\\ p+5\left( \boxed{56-p} \right)=152 \end{cases}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%0Ap%2Bn%3D56%5Cimplies%20%5Cboxed%7Bn%7D%3D56-p%5C%5C%0Ap%2B5n%3D152%5C%5C%0A----------%5C%5C%0Ap%2B5%5Cleft%28%20%5Cboxed%7B56-p%7D%20%5Cright%29%3D152%0A%5Cend%7Bcases%7D)
solve for "p", to see how many penny coins are there.
what about the nickels? well, n = 56 - p.