The zeroes of the polynomial functions are as follows:
- For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
- For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
- For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
<h3>What are the zeroes of a polynomial?</h3>
The zeroes of a polynomial are the vales of the variable which makes the value of the polynomial to be zero.
The polynomials are given as follows:
f(x) = 2x(x - 3)(2 - x)
f(x) = 2(x - 3)²(x + 3)(x + 1)
f(x) = x³(x + 2)(x - 1)
For the polynomial, f(x) = 2x(x - 3)(2 - x), the zeroes are 3, 2
For the polynomial, f(x) = 2(x - 3)²(x + 3)(x + 1), the zeroes are 3, - 3, and -1
For the polynomial, f(x) = x³(x + 2)(x - 1), the zeroes are -2, and 1
In conclusion, the zeroes of a polynomial will make the value of the polynomial function to be zero.
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Answer:
3 y + 14
Step-by-step explanation:
(hope this helps can i plz have brainlist :D hehe)
X-intercept = -3
y- intercept = -6
9514 1404 393
Answer:
the lines are perpendicular
Step-by-step explanation:
You can tell something by looking at the differences of coordinates:
B-A = (6-2, -11-5) = (4, -16) . . . . . Δy/Δx = -16/4 = -4
D-C = (-1-3, 9-10) = (-4, -1) . . . . . Δy/Δx = -1/-4 = 1/4
The product of the slopes of these lines is (-4)(1/4) = -1, so ...
the lines are perpendicular
After factoring 
the solutions are x=0 , x=3, x= -3
Step-by-step explanation:
We need to solve by factoring:
Solving:
Taking 3x common:
Now using formula 
So, After factoring the solutions are x=0 , x=3, x= -3
Keywords: Factorization
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