All categories

3 years ago

Can someone help me with question 1 and 2 please

Mathematics

1 answer:

klasskru [66]3 years ago

5 0

Question 1)
there’s 180 degrees in a triangle
70 + 70 = 140
180 - 140= 40
A= 40
question 2)
there’s only one line of symmetry, down the middle

You might be interested in

Find the value of 3/4 + 1/5 cannnnnn anyone helppp!???

Oxana [17]

Value of 3/4 + 1/5 is 19/20.

Do you need the steps?

First, calculate the LCM of the denominators (4 and 5) which is 20.

Now, divide 20 by 4 and 5 and multiply the quotient with the numerator.

(5×3) + (4×1)

=> 15+4

=> 19/20

Hope it helps!

Please mark as brainliest :D

8 0

3 years ago

Read 2 more answers

Question 6 options: What is the approximate area of a circle with a diameter of 56 cm? Use your calculator button for π. Round y

Andrew [12]

The area of circle is 2463.0086 cm².

Step-by-step explanation:

Given,

Diameter of circle = 56 cm

Radius of circle = $\frac{Diameter}{2}$

Radius of circle = $\frac{56}{2}=28\ cm$

We know that;

Area of circle = $\pi r^2$

Area of circle = $\pi *(28)^2$

Area of circle = π * 784

Area of circle = 2463.00864041 cm²

Rounding off to four decimal places

Area of circle = 2463.0086 cm²

The area of circle is 2463.0086 cm².

Keywords: area, circle

Learn more about area at:

#LearnwithBrainly

8 0

3 years ago

I need help due tmrw

White raven [17]

Answer:

yo ill help you but do you happen to have a argumentative essay written ill help u if you help me

3 0

2 years ago

Rob's family ate 3 5/8 pizzas at a local restaurant. Each pizza weighs 1 1/4 kg. Which expression can be used to determine how m

aleksklad [387]

Answer:

Step-by-step explanation:

4 0

3 years ago

Tính tích phân sau bằng cách dùng tọa độ cực I=∫∫ <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B%5Csqrt%7Bx%5E%7B2%7D%20%2B

xenn [34]

It sounds like R is the region (in polar coordinates)

R = {(r, θ) : 2 ≤ r ≤ 3 and 0 ≤ θ ≤ π/2}

Then the integral is

$\displaystyle \iint_R\frac{\mathrm dx\,\mathrm dy}{\sqrt{x^2+y^2}} = \int_0^{\pi/2}\int_2^3 \frac{r\,\mathrm dr\,\mathrm d\theta}{\sqrt{r^2}} \\\\ = \int_0^{\pi/2}\int_2^3 \mathrm dr\,\mathrm d\theta \\\\ = \frac\pi2\int_2^3 \mathrm dr \\\\ = \frac\pi2r\bigg|_2^3 = \frac\pi2 (3-2) = \boxed{\frac\pi2}$

5 0

3 years ago

Can someone help me with question 1 and 2 please​

Can someone help me with question 1 and 2 please