The disclosure paradigm has as its assumptions that an attacker will learn little or nothing from disclosure is known as Open source.
<h3>What is open source?</h3>
An Open source is known to be a term that connote that is said to be an Open source software set up to be publicly used by people.
Therefore, The disclosure paradigm has as its assumptions that an attacker will learn little or nothing from disclosure is known as Open source.
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Answer:
The answer to this question is given below in the explanation section.
Explanation:
The correct answer to this question is initialization.
When you write a variable in a program, for example int firstNumber. The integer variable firstNumber is declaring in the program.
when you assign a data value to a variable in a program is referred to as initialization. for example:
firstNumber=10;
You can declare and initialize the variable in one statement such as:
int firstNumber=10;
Answer:
An answer to this question is given below in explanation section.
Explanation:
The given question is incomplete. First, we write the complete question that is:
Suppose Client A initiates a Telnet session with Server S. At about the same time, Client B also initiates a Telnet session with Server S. Run telnet in a terminal and capture the traffic on Wireshark. For example, open a telnet session using this command: "telnet cs537.cs.csusm.edu". What are the source and destination port numbers for the following items?
- the segment sent from A to S.
- the segment sent from B to S.
- the segment sent from S to A.
- the segment sent from S to B.
- if A and B are different hosts, is it possible that the source port number in the segments from A to S is the same as that from B to S?
- how about if they are the same host?
Answers
Source Port Numbers Destination Port Number
- A -> S 1467 23
- B -> S 1513 23
- S->A 23 1467
- S->B 23 1513
- Yes, it is that the source port number in the segement from A to S is the same as that from B to S. In short, there is no relationship between port numbers on different hosts
- no, a port number identify UNIVOCALLY a process.
