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Misha Larkins [42]
2 years ago
14

Find the domain of the following expression 15 - √(x+2)

Mathematics
1 answer:
ipn [44]2 years ago
6 0

Answer:

[-2, ∞]

Step-by-step explanation:

15 - √(x+2)

domain is any value as long as (x+2) is not-negative, since √ of a negative number has no Real solution.

x+2 ≥ 0 ⇒ x ≥ -2

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José put $1,500 into a savings account. He earns 3% interest every year. How much simple interest will he earn at the end of 3 y
stiv31 [10]

He would have a total of: $1639.09

In intrest alone he would've made 1639.09

Step-by-step explanation:

3%= 0.03

  • The first thing you do is multiply $1,500 by the %3 (0.03).

  • When your done multiplying, you should get 45.

  • Add 45 to 1500

  • Now you have 1545

  • Then you repeat the process over, two more times. However the numbers will change.

7 0
2 years ago
The formula F=95C+32 changes a temperature reading from the Celsius scale C to the Fahrenheit scale F. What is the temperature m
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Answer:

122°F

Step-by-step explanation:

F=(50×9/5)+32

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8 0
2 years ago
A psychological experiment was conducted to investigate the length of time (time delay) between the administration of a stimulus
aleksklad [387]

Answer:

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

The significance level for this test is 0.05.

Step-by-step explanation:

In this case, we want to prove if there is significant evidence that the mean differs from 1.6 seconds. That is the same as having evidence to reject the the hypothesis H_0:\mu= 1.6 (the null hypothesis always have the equal sign).

We have to test the null hypothesis

H_0:\mu= 1.6

The significance level for this test is 0.05

Calculation of the t-statistic:

t=\frac{M-\mu}{s/\sqrt{n}} =\frac{2.2-1.6}{0.57/\sqrt{36}} =\frac{0.6}{0.063}= 9.47

If we look up in a t-table for t=9.47 and df=(36-1)=35, we get this value appears with a probability of zero. A large number like that is very unlikely to happen.

The P-value of this sample is 0 and is less than the significance level (0.05), so the effect is significant and the null hypothesis is rejected.

As there is significant evidence to reject H_0: \mu= 1.6, we can say that there is significant evidence to claim that the mean time delay for the hypothetical population of all persons who may be subjected to the stimulus differs from 1.6 seconds.

6 0
2 years ago
3x(x-2)-x^2+4=0<br> Help
antoniya [11.8K]

Answer:

x=2,1 solving with quadratic formula

Step-by-step explanation:

3 0
3 years ago
The quotient of z and 10 increased by 32
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.,.,.,.,7.,.,.,.,. ,                                                                    

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