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sineoko [7]
2 years ago
5

Find the length indicated

Mathematics
2 answers:
disa [49]2 years ago
8 0

Answer:

7

Step-by-step explanation:

K is the midpoint of JL, so half of 14is 7

defon2 years ago
3 0

Answer:

I think its 7 but im not sure

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On the first day it was posted online, a music video got 510 views. The number of views that the video got each day increased by
8090 [49]

Answer:

19,552 views on day 20, 114,763 views cumulative total for 20 days.

Step-by-step explanation:

The decimal equivalent to "increased by 20% per day" would be (510)*(1.20)/day, if we started with 510 views as day 0.  Day 1 would be (510)*(1.20) = 612 views.

If we have n successively days, the equation would read (510)(1.20)^n.

This means that after, lets say, 3 days, the calculation would be (510)*(1.20)^3, or 881 views.

On day 20, the calculation is (510)*(1.2)^20, or 19,552 views.

But the question asks "How many total views did the video get over the course of the first 20 days . . ?"  This seems to be asking the sum of the first 20 days, which is easy if you use a spreadsheet.  But if you read the question to mean what are the total views on day 20, the answer would be 19,552 views.

If you read the question as asking for the total sum of views over 30 days, the answer is 114,763.  Quick:  what does that amount to at $0.05 per view.

3 0
3 years ago
Can you help me find the side??? It's trigonometry!!
olganol [36]

Answer: 5.6

===================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(B) = AB/BC

cos(62) = AB/12

12*cos(62) = AB

AB = 12*cos(62)

AB = 5.63365875

AB = 5.6

8 0
3 years ago
WILL GIVE 100 POINTS AND MAYBE BRAINLIEST
Anon25 [30]

Answer:

y=\cfrac{1}{2}\;x-4

x   |  y

10    1    = 1/2 (10) -4=5-5= 1

-2    -5  = 1/2(-2)-4=-1-4= -5

4     -2   = 1/2(4)-4=2-4= -2

-8    -8  = 1/2(-8)-4=-4-4= -8

4 0
2 years ago
Determine the values of xfor which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001.(Enter
MrMuchimi

Answer:

The values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

Step-by-step explanation:

Note: This question is not complete. The complete question is therefore provided before answering the question as follows:

Determine the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001. f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0

The explanation of the answer is now provided as follows:

Given:

f(x) = e^x ≈ 1 + x + x²/2! + x³/3!, x < 0 …………….. (1)

R_{3} = (x) = (e^z /4!)x^4

Since the aim is R_{3}(x) < 0.001, this implies that:

(e^z /4!)x^4 < 0.0001 ………………………………….. (2)

Multiply both sided of equation (2) by (1), we have:

e^4x^4 < 0.024 ……………………….......……………. (4)

Taking 4th root of both sided of equation (4), we have:

|xe^(z/4) < 0.3936 ……………………..........…………(5)

Dividing both sides of equation (5) by e^(z/4) gives us:

|x| < 0.3936 / e^(z/4) ……………….................…… (6)

In equation (6), when z > 0, e^(z/4) > 1. Therefore, we have:

|x| < 0.3936 -----> 0 < x < 0.3936

Therefore, the values of x for which the function can be replaced by the Taylor polynomial if the error cannot exceed 0.001 is 0 < x < 0.3936.

3 0
3 years ago
PLEASE HELP I NEED AN ANSWER QUICK
juin [17]

Answer:

- first option is incorrect

- second option is correct

- third option is correct

- fourth option is correct

Step-by-step explanation:

grammarly xoxo

5 0
3 years ago
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