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3 years ago

15

Line Q is represented by the following equation: 2x + y = 11

2 answers:

SpyIntel [72]3 years ago

6 0

Answer:

Hi your answer is B, x + y = 15. Have a nice day!

Step-by-step explanation:

anyanavicka [17]3 years ago

5 0

Answer:

the second one.

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Help please !!!!!!!!

Ugo [173]

Answer:

y = -4

x = 3

Step-by-step explanation:

Let's first explain when x = 0

Find where x = 0 on the graph. We are finding what the y-value would be. Trace down the y-axis along the vertical line x = 0. Where does the line intersect the y-axis when x = 0? The answer would be -4

The y-intercept is -4, and the x-value for this is 0, of course. So the correct answer for when x = 0 would be y = -4.

Next, we are told to find x when y = -2. Find where y = -2. Now, staying at y = -2, go horizontally along the x-axis at y = -2 until you reach the line. Boom! You should have connected up with the line at around x = 3. Therefore, when y = -2, x = 3

8 0

3 years ago

A survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 sen

tatyana61 [14]

Answer:

96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

Step-by-step explanation:

We are given that a survey was conducted to determine the average age at which college seniors hope to retire in a simple random sample of 101 seniors, 55 was the average desired retirement age, with a standard deviation of 3.4 years.

Firstly, the Pivotal quantity for 96% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample average desired retirement age = 55 years

$\sigma$ = sample standard deviation = 3.4 years

n = sample of seniors = 101

$\mu$ = true mean retirement age of all college students

<em>Here for constructing 96% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

<u>So, 96% confidence interval for the population mean, </u> $\mu$ <u> is ;</u>

P(-2.114 < $t_1_0_0$ < 2.114) = 0.96 {As the critical value of t at 100 degree

of freedom are -2.114 & 2.114 with P = 2%}

P(-2.114 < $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ < 2.114) = 0.96

P( $-2.114 \times {\frac{s}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.114 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

P( $\bar X-2.114 \times {\frac{s}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.114 \times {\frac{s}{\sqrt{n} } }$ ) = 0.96

<u>96% confidence interval for</u> $\mu$ = [ $\bar X-2.114 \times {\frac{s}{\sqrt{n} } }$ , $\bar X+2.114 \times {\frac{s}{\sqrt{n} } }$ ]

= [ $55-2.114 \times {\frac{3.4}{\sqrt{101} } }$ , $55+2.114 \times {\frac{3.4}{\sqrt{101} } }$ ]

= [54.30 , 55.70]

Therefore, 96% confidence interval for desired retirement age of all college students is [54.30 , 55.70].

7 0

3 years ago

sandy is cutting bows out of ribbon which will be used to rap gifts. If sandy need 9/7 feet of ribbon to make a bow and she has

Katarina [22]

Sandy can make 14 bows

3 0

3 years ago

Please help me out with this

andre [41]

Answer:

$\huge\boxed{\sqrt[3]{c^4}=c^\frac{4}{3}}$

Step-by-step explanation:

$\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\text{therefore}\\\\\sqrt[3]{c^4}=c^\frac{4}{3}$

5 0

3 years ago

Help will mark Brainliest

yarga [219]

Answer:

C. is the correct answer

Step-by-step explanation:

A. is incorrect because the sequence does not start with 15

B. is incorrect because the pattern increases by 5, not multiplied by 5

C. is correct because all of the even numbers in the pattern do end in 0

D. is incorrect because even numbers don't end in 5's

Hope this helps!

5 0

2 years ago

Read 2 more answers