Answer:
The magnitude of the magnetic moment of the rotating ring is
Explanation:
Given that,
Radius = 2.2 cm
Charge
Angular speed = 2.01 rad/s
We need to calculate the time period
Now, The spinning produced the current
Using formula for current
We need to calculate the magnetic moment
Using formula of magnetic moment
Put the value of I and A into the formula
Put the value into the formula
Hence, The magnitude of the magnetic moment of the rotating ring is
Since you're giving us the original and final volumes, as well as the mass, and all you want to know is density, we don't actually care about temperature or pressure. Let um do whatever they want to do.
The new mass is the same as the original mass ... 4 grams.
The new volume is 50 cm³.
The new density is (mass)/(volume) = (4g) / (50 cm³) = <em>0.08 g/cm³</em>
We know that P1V1 = P2V2, if there is a constant pressure, then the P1 and P2 can cancel out, so it is V1=V2 that is whats left.
Answer:
A. Sliding friction
Explanation:
Sliding friction is weaker than static friction
Because its belong to space