Diagram A shows two laser beams, one blue and one red, that are incident on a mirrored surface. Diagram B shows two laser beams,
one blue and one red, that are incident on a transparent block of glass.
Which statement about the situation shown in these diagrams is CORRECT when light is refracted through the glass and reflected from the mirror?
A
The blue and red laser beams reflect at different angles, and they refract at different angles.
B
The blue and red laser beams reflect at the same angle, and they refract at the same angle.
C
The blue and red laser beams reflect at different angles, and they refract at the same angle.
D
The blue and red laser beams reflect at the same angle, and they refract at different angles.
Which statement about the situation shown in these diagrams is CORRECT when light is refracted through the glass and reflected from the mirror?
A
The blue and red laser beams reflect at different angles, and they refract at different angles.
B
The blue and red laser beams reflect at the same angle, and they refract at the same angle.
C
The blue and red laser beams reflect at different angles, and they refract at the same angle.
D
The blue and red laser beams reflect at the same angle, and they refract at different angles.
1 answer:
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Answer:
120 volts is the root mean square (rms) average of the voltage as it varies with time.
Explanation:
A. The average voltage over many weeks of time (false)
Reason: Average AC voltage over one cycle is cycle (from one peak to other) is zero and so over many weeks of time it is zero.
B. The peak voltage from an AC wall receptacle (false)
Reason: The peak voltage of an AC source in North America is zero.
C. The arithmetic mean of the voltage as it varies with time (false)
Reason: Arithmetic mean AC voltage over one cycle is cycle (from one peak to other) is zero and so over many weeks of time it is zero.
D. One-half the peak voltage (false)
Peak voltage =170 Volts
One-half the peak voltage = 85 volts
E. The root mean square (rms) average of the voltage as it varies with time (True)
Reason:
The peak voltage and root mean square voltage are related by:
Average value of voltage over one cycle is zero, so instead of calculating average voltage for AC peak voltage is first squared and the mean is calculated.
Answer:
Let's define t = 0s (the initial time) as the moment when Car A starts moving.
Let's find the movement equations of each car.
A:
We know that Car A accelerations with a constant acceleration of 5m/s^2
Then the acceleration equation is:
To get the velocity, we integrate over time:
Where V₀ is the initial velocity of Car A, we know that it starts at rest, so V₀ = 0m/s, the velocity equation is then:
To get the position equation we integrate again over time:
Where P₀ is the initial position of the Car A, we can define P₀ = 0m, then the position equation is:
Now let's find the equations for car B.
We know that Car B does not accelerate, then it has a constant velocity given by:
To get the position equation, we can integrate:
This time P₀ is the initial position of Car B, we know that it starts 100m ahead from car A, then P₀ = 100m, the position equation is:
Now we can answer this:
1) The two cars will meet when their position equations are equal, so we must have:
We can solve this for t.
This is a quadratic equation, the solutions are given by the Bhaskara's formula:
We only care for the positive solution, which is:
Car A reaches Car B after 11.48 seconds.
2) How far does car A travel before the two cars meet?
Here we only need to evaluate the position equation for Car A in t = 11.48s:
3) What is the velocity of car B when the two cars meet?
Car B is not accelerating, so its velocity does not change, then the velocity of Car B when the two cars meet is 20m/s
4) What is the velocity of car A when the two cars meet?
Here we need to evaluate the velocity equation for Car A at t = 11.48s