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3 years ago

A 400.0 ohm resistor has a potential difference of 20.0 volts. What is the magnitude of the power dissipated by the resistor

Physics

1 answer:

Sergio [31]3 years ago

3 0

P=IV, where P is power, I is resistance, and V is voltage. Plug in and solve:

P=400(20)

P=8000W

Hope this helps!!

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It takes a car 1.75 h to go from mile marker 10 to mile marker 115. What is the average speed of the car? Someone who took this

givi [52]

The distance from mile-mark 10 to mile-mark 115 is (115-10) = 105 miles.

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Speed = (105 miles) / (1.75 hours)

Speed = (105/1.75) (mi/hr)

<em>Speed = 60 mph</em> (B)

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3 years ago

A balloon rises at the rate of 8 feet per second from a point on the ground 12 feet from an observer. To 2 decimal places in rad

Hitman42 [59]

Answer:

$\displaystyle \theta' =0.24\ rad/s$

Explanation:

<u>Rate Of Change</u>

Let some variable y depend on time t. we can express y as a function of t as

$y=f(t)$

The instant rate of change of y respect to t is the first derivative, i.e.

$y'=f'(t)$

The balloon, the ground and the observer form a right triangle (shown below) where the height of the balloon y, the horizontal distance x, and the angle of elevation are related with the trigonometric formula

$\displaystyle tan\theta =\frac{y}{x}$

Since x is constant, we take the derivative with respect to time by using the chain rule:

$\displaystyle sec^2\theta \ \theta' =\frac{y'}{x}$

Solving for $\theta'$

$\displaystyle \theta' =\frac{y'}{xsec^2\theta}$

Let's compute the actual angle with the initial conditions y=9 feet, x=12 feet

$\displaystyle tan\theta =\frac{y}{x}$

$\displaystyle tan\theta =\frac{9}{12}=\frac{3}{4}$

Knowing that

$\sec^2\theta=1+tan^2\theta$

$\displaystyle \sec^2\theta=1+\left(\frac{3}{4}\right)^2$

$\displaystyle \sec^2\theta=\frac{25}{16}$

The balloon is rising at y'=8 feet/sec, thus we compute the change of the angle of elevation:

$\displaystyle \theta' =\frac{8}{12\ \frac{25}{16}}$

$\displaystyle \theta' =\frac{32}{75}\ rad/s$

$\boxed{\displaystyle \theta' =0.43\ rad/s}$

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Why are we unlikely to find earth-like planets around halo stars in the galaxy? why are we unlikely to find earth-like planets a

charle [14.2K]

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