Can someone please help me with this question??

Mathematics

1 answer:

WARRIOR [948]3 years ago

8 0

If the entire student population seems a lot higher than 10 people, I say no. It just depends on the student population. Please look at the earlier parts and respond with a comment what the entire student population is, but if there is no specifications, I would assume they should find a larger sample because 10 people is not accurate to find a general opinion over a larger population.

You might be interested in

Plsss help i do not understand this:(

Ivahew [28]

Answer: ( 2, -3/2)

Using the midpoint formula:

(x1 + x2), (y1 + y2)
———. ———-
2. 2

(2 + 2), (-7+4)
——. ——
2. 2

( 2, -3/2)

5 0

3 years ago

Help Please! :) Fast as you can!

swat32

It’s d, 1 - t

t + 3 - 2 - 2t
we can rearrange it as
t - 2t + 3 - 2
-t + 1 is the same as 1 - t

5 0

3 years ago

Read 2 more answers

A firework is launched at the rate of 10 feet per second from a point on the ground 50 feet from an observer. to 2 decimal place

Kazeer [188]

The rate of change of the angle of elevation when the firework is 40 feet above the ground is 0.12 radians/second.

First we will draw a right angle triangle ΔABC, where ∠B = 90°

Lets, assume the height(AB) = h and base(BC)= x

If the angle of elevation, ∠ACB = α, then

tan(α) = $\frac{AB}{BC} = \frac{h}{x}$

Taking inverse trigonometric function, α = tan⁻¹ ( $\frac{h}{x}$ ) .............(1)

As we need to find the rate of change of the angle of elevation, so we will differentiate both sides of equation (1) with respect to time (t) :

$\frac{d\alpha}{dt}=[\frac{1}{1+ \frac{h^2}{x^2}}]*(\frac{1}{x})\frac{dh}{dt}$

Here, the firework is launched from point B at the rate of 10 feet/second and when it is 40 feet above the ground it reaches point A,

that means h = 40 feet and $\frac{dh}{dt}$ = 10 feet/second.

C is the observer's position which is 50 feet away from the point B, so x = 50 feet.

$\frac{d\alpha}{dt}= [\frac{1}{1+ \frac{40^2}{50^2}}] *\frac{1}{50} *10\\ \\ \frac{d\alpha}{dt} = [\frac{1}{1+\frac{16}{25}}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt} = [\frac{25}{41}] *\frac{1}{5}\\ \\ \frac{d\alpha}{dt}= \frac{5}{41} =0.1219512$

= 0.12 (Rounding up to two decimal places)

So, the rate of change of the angle of elevation is 0.12 radians/second.

5 0

3 years ago

Cylinders A and B are similar. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

MrRa [10]

The question is incomplete. The complete question is :

Cylinders A and B are similar. The length of the cylinder A is 4 mm and the length of cylinder B is 6 mm. The volume of cylinder A is 20mm3. Calculate the volume of cylinder B.

Answer:

67.5 $mm^3$