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3 years ago

5

A recipe for homemade clay calls for 6 cups of water for every 12 cups. How many cups of water are needed when 4 cups of flour a

re used ?

1 answer:

pochemuha3 years ago

6 0

Answer:

2 cups of clay

Step-by-step explanation:

Given data

we are given that 6 cups of water for every 12 cups of clay

i.e

12 cups of clay require 6 cups of water

4 cups of clay will require x cups of water

cross multiply

12x= 4*6

12x= 24

divide both sides by 12

x= 24/12

x= 2cups

Hence 4 cups of water will require 2 cups of clay

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..................help

almond37 [142]

Answer:

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Step-by-step explanation:

7 0

2 years ago

Given tan theta =9, use trigonometric identities to find the exact value of each of the following:_______

Ludmilka [50]

Answer:

$(a)\ \sec^2(\theta) = 82$

$(b)\ \cot(\theta) = \frac{1}{9}$

$(c)\ \cot(\frac{\pi}{2} - \theta) = 9$

$(d)\ \csc^2(\theta) = \frac{82}{81}$

Step-by-step explanation:

Given

$\tan(\theta) = 9$

Required

Solve (a) to (d)

Using tan formula, we have:

$\tan(\theta) = \frac{Opposite}{Adjacent}$

This gives:

$\frac{Opposite}{Adjacent} = 9$

Rewrite as:

$\frac{Opposite}{Adjacent} = \frac{9}{1}$

Using a unit ratio;

$Opposite = 9; Adjacent = 1$

Using Pythagoras theorem, we have:

$Hypotenuse^2 = Opposite^2 + Adjacent^2$

$Hypotenuse^2 = 9^2 + 1^2$

$Hypotenuse^2 = 81 + 1$

$Hypotenuse^2 = 82$

Take square roots of both sides

$Hypotenuse =\sqrt{82}$

So, we have:

$Opposite = 9; Adjacent = 1$

$Hypotenuse =\sqrt{82}$

Solving (a):

$\sec^2(\theta)$

This is calculated as:

$\sec^2(\theta) = (\sec(\theta))^2$

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

Where:

$\cos(\theta) = \frac{Adjacent}{Hypotenuse}$

$\cos(\theta) = \frac{1}{\sqrt{82}}$

So:

$\sec^2(\theta) = (\frac{1}{\cos(\theta)})^2$

$\sec^2(\theta) = (\frac{1}{\frac{1}{\sqrt{82}}})^2$

$\sec^2(\theta) = (\sqrt{82})^2$

$\sec^2(\theta) = 82$

Solving (b):

$\cot(\theta)$

This is calculated as:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

Where:

$\tan(\theta) = 9$ ---- given

So:

$\cot(\theta) = \frac{1}{\tan(\theta)}$

$\cot(\theta) = \frac{1}{9}$

Solving (c):

$\cot(\frac{\pi}{2} - \theta)$

In trigonometry:

$\cot(\frac{\pi}{2} - \theta) = \tan(\theta)$

Hence:

$\cot(\frac{\pi}{2} - \theta) = 9$

Solving (d):

$\csc^2(\theta)$

This is calculated as:

$\csc^2(\theta) = (\csc(\theta))^2$

$\csc^2(\theta) = (\frac{1}{\sin(\theta)})^2$

Where:

$\sin(\theta) = \frac{Opposite}{Hypotenuse}$

$\sin(\theta) = \frac{9}{\sqrt{82}}$

So:

$\csc^2(\theta) = (\frac{1}{\frac{9}{\sqrt{82}}})^2$

$\csc^2(\theta) = (\frac{\sqrt{82}}{9})^2$

$\csc^2(\theta) = \frac{82}{81}$

4 0

3 years ago

(2 X + 5) and (4 X - 3)

zepelin [54]

Answer: 8x+2

explanation:

i just solved it

4 0

2 years ago

Read 2 more answers

Suppose that the function f is defined. , for all real numbers, as follows.

aivan3 [116]

Answer: <em>The values of......</em>

<em> $f(-5)=\frac{9}{4}\\ \\ f(-2)= -1\\ \\ f(4)=0$ </em>

Step-by-step explanation:

Given function is: $\left \{ {{f(x)= \frac{1}{4}x^2 -4, if x\neq -2} \atop {=-1, if x=-2}} \right.$

For $f(-5),$ the value of $x$ is -5, which is not equal to -2.

So, $f(-5)= \frac{1}{4}(-5)^2 -4 = \frac{1}{4}(25)-4 =\frac{25}{4}-4=\frac{25-16}{4}=\frac{9}{4}$

For $f(-2),$ the value of $x$ is -2.

So, $f(-2)= -1$

For $f(4),$ the value of $x$ is 4, which is not equal to -2.

So, $f(4)=\frac{1}{4}(4)^2 -4 =\frac{1}{4}(16)-4 =4-4=0$

5 0

3 years ago

A recent article in the paper claims that business ethics are at an all-time low. Reporting on a recent sample, the paper claims

dedylja [7]

Answer:

The correct solution is "0.127128".

Step-by-step explanation:

The given values are:

p = 0.31

n = 20

Now,

$p(8$

$=20C_{9}(0.31)^9\times (0.69)^{11}+20C_{10}(0.31)^{10}\times (0.69)^{10}+20C_{11}\times (0.31)^{11}\times (0.69)^{9}$

$=0.074955+0.037043+0.015130$

$=0.127128$

5 0

2 years ago