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Savatey [412]
3 years ago
13

Help me ill give brainllist!!!!!!!!

Mathematics
2 answers:
katrin2010 [14]3 years ago
7 0

Answer:

the shape is semetrical

Step-by-step explanation:

sleet_krkn [62]3 years ago
5 0

Answer: The facts Ab=Dc and Ac=Db are enough to show that Triangle ABC and Triangle DBC are congruent. This means that their similar angles will be equal like their sides.

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(-4, 7) and (1, 2) point slope form and slope intercept form
Monica [59]
I’m not sure but I think graphing it would help I really don’t know what to say
3 0
3 years ago
What is the perimeter of square EFGH, shown?<br><br> A. 14.1<br> B. 28.3<br> C. 34.6<br> D. 17.3
kap26 [50]

Answer:

The perimeter of square EFGH is 28.28 units

Step-by-step explanation:

Given in the figure as :

EFGH is a square with points E,F,G,H

∵  The measure of each points from center o is same

I.e OE = OF = OG = OH = 5 units

Now, From any of two length from center o , we can measure the length of each side .

So, (OG)² + (OF)² = (GF)²

Or, (5)² + (5)² = (GF)²

Or,   25 + 25  = (GF)²

Or,     (GF)²  = 50

∴       GF =  5 \sqrt{2}  unit

Similarly each side EF, GH , EH have same length

Now, As The perimeter of square = 4 × side

So,          The perimeter of square = 4 × ( 5 \sqrt{2} )

Or,          The perimeter of square = 20 × ( \sqrt{2} ) = 28.28 unit

Hence The perimeter of square EFGH is 28.28 units   Answer

6 0
3 years ago
Write an absolute value inequality that has 3 and -6 as two of its solutions
GenaCL600 [577]

Answer:it can be 3P = -6

Step-by-step explanation:

p is equal to 3*6 so 3p=-6

7 0
4 years ago
Two sides of a triangle have the same length. The third side measures 7m less than twice the common length. The perimeter of the
Gwar [14]

Answer:

Step-by-step explanation:

I am pretty sure your answer is 3

6 0
4 years ago
Read 2 more answers
HELP PLEASE AND THANK YOU 5JAAB
Gnom [1K]

Answer:

\bold{Q17}\ \angle A\\\\\bold{Q18}\ R\\\\\bold{Q19}\ T\\\\\bold{Q20}\ \angle B\ \leftrightarrow\ \angle C

Step-by-step explanation:

Q17

\overline{WA},\ \overline{AS}\ -\ A\ \text{is common}.\ \text{Therefore your answer is}\ \angle A\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{WA}\to\angle W\\\\\text{for}\ \overline{WS}\ \text{and}\ \overline{SA}\to\angle S\\\\============================

For Q18 and Q19.

If ΔABC ≅ ΔSRT (congruent), then

A\ \leftrightarrow\ S\\ B\ \leftrightarrow\ R\\ C\ \leftrightarrow\ T\\\\============================

Q20

\text{If}\ AB\cong AC,\ BD\cong CD,\ RSTU\ \text{is a parallelogram (rectangle)},\ \text{then}\\\\\angle 1\ \leftrightarrow\ \angle2\\\angle3\ \leftrightarrow\ \angle4\\\angle C\leftrightarrow\ \angle B\\\angle 5\ \leftrightarrow\ \angle6\\\angle7\ \leftrightarrow\ \angle 8\\\angle R\ \leftrightarrow\ \angle T\\\angle S\ \leftrightarrow\ \angle U

4 0
3 years ago
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