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r-ruslan [8.4K]
3 years ago
10

Simplify the expression. Write the answer using scientific notation. (5x10^5)^-2 A. 0.04x10^-10 B. 4.0x10^-11 C. -10x10^-10 D. 4

.0x10^-12
Mathematics
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Simplify the expression

(5*10^5)^-2

It can be simplified as below:

(5*10^5)^{-2}=\frac{1}{(5*10^5)^2} \\\\(5*10^5)^{-2}=\frac{1}{25*10^{10}} \\\\(5*10^5)^{-2}=\frac{1}{25}*10^{-10}\\\\ (5*10^5)^{-2}=0.04*10^{-10}\\

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Pls answer with explanation!
patriot [66]

Answer:

3,750 cars.

Step-by-step explanation:

We are given that the equation:

y=9000-2.4x

Models the relationsip between <em>y</em>, the number of unfilled seats in the stadium, and <em>x</em>, the number of cars in the parking lot.

We want to determine the number of cars in the parking lot when there are no unfilled seats in the stadium.

When there are no unfilled seats in the stadium, <em>y</em> = 0. Thus:

0=9000-2.4x

Solve for <em>x</em>. Subtract 9000 from both sides:

-2.4x=-9000

Divide both sides by -2.4:

x=3750

So, there will be 3,750 cars in the parking lot when there are no unfilled seats in the stadium.

4 0
3 years ago
John can jog twice as fast as he can walk. He was able to jog the first mile to his grandmas house but then he got tired and wal
statuscvo [17]

Answer:

  12 mph

Step-by-step explanation:

The relationship between jogging speed and walking speed means the time it takes to walk 4 miles is the same as the time it takes to jog 8 miles. Then the total travel time (0.75 h) is the time it would take to jog 1+8 = 9 miles. The jogging speed is ...

  (9 mi)(.75 h) = 12 mi/h . . . average jogging speed

__

<em>Check</em>

1 mile will take (1 mi)/(12 mi/h) = 1/12 h to jog.

4 miles will take (4 mi)/(6 mi/h) = 4/6 = 8/12 h to walk.

The total travel time is (1/12 +8/12) h = 9/12 h = 3/4 h. (answer checks OK)

_____

<em>Comment on the problem</em>

Olympic race-walking speed is on the order of 7.7 mi/h, so John's walking speed of 6 mi/h should be considered quite a bit faster than normal. The fastest marathon ever run is on the order of a bit more than 12 mi/h, so John's jogging speed is also quite a bit faster than normal. No wonder he got tired.

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3 years ago
Four students are asked to draw a parallelgram. each drew a differently-named figure
nikitadnepr [17]
So basicly the question is asking, name 4 parrelegrams. Thr answer will be, Rectangle, Squrare Trapizoid, and Rhymbus. Not is a specifc order.
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3 years ago
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Three solutions of the equation Ax + By = Cz - 14 are
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