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r-ruslan [8.4K]

3 years ago

10

Simplify the expression. Write the answer using scientific notation. (5x10^5)^-2 A. 0.04x10^-10 B. 4.0x10^-11 C. -10x10^-10 D. 4

.0x10^-12

1 answer:

Diano4ka-milaya [45]3 years ago

5 0

Simplify the expression

$(5*10^5)^-2$

It can be simplified as below:

$(5*10^5)^{-2}=\frac{1}{(5*10^5)^2} \\\\(5*10^5)^{-2}=\frac{1}{25*10^{10}} \\\\(5*10^5)^{-2}=\frac{1}{25}*10^{-10}\\\\ (5*10^5)^{-2}=0.04*10^{-10}\\$

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I need help please, very confused on what to do!

Firdavs [7]

Step-by-step explanation:

X intercept of -5 means the line cuts the x axis at -5 so, mark with a small dot/x at - 5 on the x axis which is the horizontal line

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now, join the 2 markings together with a straight line

3 0

3 years ago

A $230 pair of shoes is on sale for 20% off at a store in Illinois. Sales Tax in Illinois is 11.5%. How Much Will The shoes end

Zepler [3.9K]

FIND SALE PRICE
= $230 - ($230*20%)
= $230 - $46
= $184

OR

= $230 * (100%-20%)
= $230 * 80%
= $184

*use the method you're most comfortable with or that your teachers prefer

FIND TOTAL WITH TAX
= $184 + ($184 * 11.5%)
= $184 + $21.16
= $205.16

ANSWER: The shoes with discount and taxes cost $205.16.

Hope this helps! :)

8 0

3 years ago

Please help, will mark Brainliest.

matrenka [14]

If f(x) = 0 then

solutions

x = 7 , x = -4

hope it helps

3 0

3 years ago

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits? Assume that repetitio

timofeeve [1]

Answer:

There are 6,151,600,000 different 7-place license plates are possible when 3 of the entries are letters and 4 are digits,

Step-by-step explanation:

For each of the entries which are letters, there are 26 possible outcomes.

For each of the entries which are digits, there are 10 possible outcomes.

These outcomes can be permutated.

For example, ABC1234 is a different outcome than A1B2C34. This means that we need to use the permutations formula.

The number of permutations of n, divided into two groups of size a and b, is:

$P_{a,b}^{n} = \frac{n!}{a!b!}$ .

In this problem, we have a permutation of 7, divided into a group of 4(digits) and 3(letters).

How many different 7-place license plates are possible when 3 of the entries are letters and 4 are digits?

This is $P_{3,4}^{7}*(26)^{3}*10^{4} = 35*(26)^{3}*10^{4} = 6,151,600,000$

There are 6,151,600,000 different 7-place license plates are possible when 3 of the entries are letters and 4 are digits,

7 0

3 years ago

What is 27a plus 24 in math

anygoal [31]

You have to figure out what “a” is equal to but if you do not have enough information given then the final answer would be “27a+24” I’m it’s simplest form

3 0

3 years ago

Read 2 more answers