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Natasha2012 [34]
3 years ago
14

Determine whether the following arguments are inductive or deductive. If an argument is inductive, determine whether it is stron

g or weak. If it is deductive, determine whether it is valid or invalid. When a cook cannot recall the ingredients in a recipe, it is appropriate that she refresh her memory by consulting the recipe book. Similarly, when a student cannot recall the answers during a final exam, it is appropriate that she refresh her memory by consulting the textbook.
Mathematics
1 answer:
Akimi4 [234]3 years ago
3 0

Answer:

inductive; weak

Step-by-step explanation:

The argument is inductive because the main point of the argument or theory was presented later at the end of the argument, after opening the argument with anecdotal evidence or observations. However, no matter how true the premises may seem to be, the argument is weak, because the conclusion is false and does not really follow from the premises. Nothing in her premises suggests consulting her textbook during final exams is acceptable. Consulting textbook during exams is certainly a prohibited act, and as such, is not the best way to refresh her memory.

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute
hoa [83]

Answer:

Obese people

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, "almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ)".

Solution to the problem

Obese people

Let X the random variable that represent the minutes of a population (obese people), and for this case we know the distribution for X is given by:

X \sim N(373,67)  

Where \mu=373 and \sigma=67

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 373- 2(67) = 239

Upper = \mu + 2\sigma = 373+ 2(67) = 507

Lean People

Let X the random variable that represent the minutes of a population (lean people), and for this case we know the distribution for X is given by:

X \sim N(526,107)  

Where \mu=526 and \sigma=107

On this case we know that 95% of the data values are within two deviation from the mean using the 68-95-99.7 rule so then we can find the limits liek this:

Lower = \mu - 2\sigma = 526- 2(107) = 312

Upper = \mu + 2\sigma = 526+ 2(107) = 740

The interval for the lean people is significantly higher than the interval for the obese people.

5 0
2 years ago
In art class, Arthur has created a triangle painting 1/5 of his painting is purple. He decided he wants to Paint 4/8 of the purp
babymother [125]

\frac{1}{10} part of the whole painting is gold colored.

<u>Solution:</u>

Given that , In art class, Arthur has created a triangle painting \frac{1}{5} of his painting is purple.  

He decided he wants to Paint \frac{4}{8} of the purple area gold  

We have to find what fraction of the whole painting will be painting?  

Now, \frac{1}{5} part of whole painting is purple

And, \frac{4}{8} part of the purple area is gold ⇒ \frac{4}{8} part of the \frac{1}{5} part of whole painting is gold

\text { Then, fraction of gold color }=\frac{4}{8} \times \frac{1}{5}=\frac{1}{2} \times \frac{1}{5}=\frac{1}{10}

Hence, \frac{1}{10} part of the whole painting is gold colored.

4 0
2 years ago
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Dafna11 [192]
you got all right just check it and do the other one
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3 years ago
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Answer: on the number line put -1.50 (1 and a half (1 1/2))

Step-by-step explanation:

$1.50 more than his account is $200.

the balance should be $-1.50

on the number line put -1.50

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I=2,400×0.07
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