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3 years ago

The owner of a garden center pays $12 for each birdbath. She sells them for 55% more than she

Mathematics

2 answers:

postnew [5]3 years ago

5 0

A I think is correct

11Alexandr11 [23.1K]3 years ago

4 0

Answer:

Step-by-step explanation:

payed price =12

so, selling price = 1.55 * 12 = b

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Please help they are separate questions please help me with this!

monitta

Answer: Mary makes $1160, Steven makes $142.50

Step-by-step explanation:

Facts

MARY

8% commision on everything she sells

She sells a car for $14,500

The first question about Mary asks how much commision she makes. To find that, lets find 8% of 14,500

8% of 14,500= 0.08x14,500= 1160

Therefore, Mary makes $1,160 in commision.

STEVEN

Facts

He makes 15% in commision for the supplies he sells

He sells $950 in supplies

Money made =?

15% of 950=0.15x950=$142.50

6 0

2 years ago

A psychologist is interested in constructing a 99% confidence interval for the proportion of people who accept the theory that a

Leona [35]

Answer:

B is correct i think

Step-by-step explanation:

4 0

3 years ago

Divide.<br><br> (<img src="https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20" id="TexFormula1" title=" x^{2} " alt=" x^{2} " align="absm

Maksim231197 [3]

(x+6)^2
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x^4+11x+30

6 0

3 years ago

Which of the following terms is two lines that lie within the same plane and never intersect?

Margaret [11]

Parallel lines never intersect

4 0

3 years ago

Read 2 more answers

Find the angle between the given vectors to the nearest tenth of a degree. u = <-5, -4>, v = <-4, -3> (1 point)

sesenic [268]

Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

<u>Step-by-step explanation:</u>

We have , two vectors u = <-5, -4>, v = <-4, -3> or , $u = -5i-4j , v=-4i-3j$

We need to find angle between these two vectors . Let's find out:

We know that dot product of two vectors is defined as :

$u.v =|u|(|v|)cosx$ , where x is angle between u & v !

⇒ $u.v =|u|(|v|)cosx$

⇒ $cosx =\frac{u.v}{|u|(|v|)}$

Now , $u.v = (-5i-4j)(-4i-3j)$

⇒ $u.v = (-5i-4j)(-4i)-(-5i-4j)(3j)$

⇒ $u.v = 20+12$ { $i(j) = j(i) =0$ }

⇒ $u.v = 32$

Now , Modulus of any vector $r = xi+yj$ is $|r| = \sqrt{x^{2}+y^{2}}$ So ,

$|u| = \sqrt{(-5)^{2}+(-4)^{2}} = \sqrt{25+16} = \sqrt{41} \\\\|v| = \sqrt{(-4)^{2}+(-3)^{2}} = \sqrt{16+9} = \sqrt{25} = 5$

Putting all these values in equation $cosx =\frac{u.v}{|u|(|v|)}$ we get:

⇒ $cosx =\frac{32}{5(\sqrt{41})}$

⇒ $cos^{-1}(cosx) =cos^{-1}(\frac{32}{5(6.4)})$

⇒ $x =cos^{-1}(1)$ { $cos0 = 1$ }

⇒ $x =0$ °

Therefore , Angle between $u = -5i-4j , v=-4i-3j$ is $x =0$ ° .

8 0

3 years ago