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Gala2k [10]
3 years ago
12

Can someone pls help me ! I’ll give u brainliest

Mathematics
1 answer:
Yanka [14]3 years ago
3 0

Answer

= Draw a segment. Label the point S on the segment.

= Draw an arc with center P. Using the same radius, draw an center with S. Label the point where the arc intercepts the new segment T.

= Draw an arc with radius QR and center T . Label the intersection of the two arcs U

= Draw S. TSU=QPR

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0.000000205<br> In standard form
zalisa [80]

Answer:

2.05 × 10⁷

Step-by-step explanation:

0.000000205

We'll move the decimal point after the first non-zero digit (as per the scientific notation rules) and the standard form would be :

=> 2.05 × 10⁷

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3 years ago
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What is the answer to question 1 written as an ordered pair? (5, $5.25)
shusha [124]
11.25,5 maybe I dunno
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If y=5x-7, determine the value of y when x=-3
alexdok [17]

Answer:-22

Step-by-step explanation:

5 times -3 equals -15, and the combine it with -7 to get -22

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Consider f and c below. f(x, y) = x2 i + y2 j c is the arc of the parabola y = 2x2 from (−1, 2) to (1, 2) (a) find a function f
Korvikt [17]
If there is some scalar function f(x,y) such that

\nabla f(x,y)=\mathbf f(x,y)=x^2\,\mathbf i+y^2\,\mathbf j

then we want to find f such that

\dfrac{\partial f}{\partial x}=x^2\implies f(x,y)=\dfrac{x^3}3+g(y)
\dfrac{\partial f}{\partial y}=y^2=\dfrac{\mathrm dg}{\mathrm dy}\implies g(y)=\dfrac{y^3}3+C
\implies f(x,y)=\dfrac{x^3}3+\dfrac{y^3}3+C

So the vector field \mathbf f(x,y) is conservative, which means the fundamental theorem applies; the line integral of \mathbf f along any path \mathcal C parameterized by some vector-valued function \mathbf r(t) over a\le t\le b is given by

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=\int_{t=a}^{t=b}\mathbf f(\mathbf r(t))\cdot\dfrac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt=f(\mathbf r(b))-f(\mathbf r(a))

In this case,

\displaystyle\int_{\mathcal C}\mathbf f\cdot\mathrm d\mathbf r=f(1,2)-f(-1,2)=\dfrac23
5 0
3 years ago
-2x + 4 = -3x + 4<br> 3<br> One Solution<br> No Solution<br> Infinite Solutions
iogann1982 [59]

Answer:

X=0 or no solution

Step-by-step explanation:

-2x+4=-3x+4

cancel equal terms on both sides of the equation

-2x=-3x

move the variable to the left-hand side and change its sign

-2x+3x=0

collect like terms

x=0

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