How could you represent the following scenarios on a graph ?

It has been reported that the probability that an individual will develop schizophrenia over their lifetime is 0.004. In a rando

Alinara [238K]

Answer:

Null hypothesis: $p=0.004$

Alternative hypothesis: $p \neq 0.004$

$z=\frac{0.00567 -0.004}{\sqrt{\frac{0.004(1-0.004)}{3000}}}=1.449$

$p_v =2*P(z>1.149)=0.2506$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion if individuals that developed schizophrenia its not significantly different from 0.004.

Step-by-step explanation:

1) Data given and notation

n=3000 represent the random sample taken

X=17 represent the individuals developed schizophrenia in the sample

$\hat p=\frac{17}{3000}=0.00567$ estimated proportion of individuals developed schizophrenia in the sample

$p_o=0.004$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that true proportion of people who will develop schizophrenia is different from 0.004:

Null hypothesis: $p=0.004$

Alternative hypothesis: $p \neq 0.004$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.00567 -0.004}{\sqrt{\frac{0.004(1-0.004)}{3000}}}=1.449$

4) P value

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>1.149)=0.2506$

5) Decision

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion if individuals that developed schizophrenia its not significantly different from 0.004.

4 0

4 years ago

Find the sum of the first one hundred positive integers. see fig 6.26

nignag [31]

Here's a pattern to consider:
1+100=101
2+99=101
3+98=101
4+97=101
5+96=101
.....
This question relates to the discovery of Gauss, a mathematician. He found out that if you split 100 from 1-50 and 51-100, you could add them from each end to get a sum of 101. As there are 50 sets of addition, then the total is 50×101=5050
So, the sum of the first 100 positive integers is 5050.

Quick note
We can use a formula to find out the sum of an arithmetic series:
$s = \frac{n(n + 1)}{2}$
Where s is the sum of the series and n is the number of terms in the series. It works for the above problem.

8 0

3 years ago

You are driving to visit a friend in another state who lives 440 miles away. You are driving 55 miles per hour and have already

irakobra [83]

Write the equation like this: 275 + 55h = 440. Then, subtract 275 on both sides making the left side cancel out and the right side 165. Lastly, divide 55 on both sides to get h all by itself. The solution is h = 3. You must drive 3 hours longer to reach your destination.

7 0

4 years ago

Read 2 more answers

A store owner paid 8.20 each for shirts. and sold them for 20.50 each. what was the percent markup

77julia77 [94]

Devon exercised the same amount of time each day for 5 days last week. 0 His exercise included ... What amount did Jessica pay to rent each movie? $12-25.

I THINK

4 0

3 years ago

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A shopkeeper has to pay 7% bonus for selling some goods. If he paid Rs 17,500 bonus and then 13% VAT, what will be marked price

JulsSmile [24]

Sjsnddjdjxnediebdudbejfbeixbdxixbxxi

5 0

3 years ago