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2 years ago

Identify the variable expression that is not a polynomial.

Mathematics

2 answers:

torisob [31]2 years ago

7 0

Answer:

B is the correct answer.

Hope this helps you!!

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alexira [117]2 years ago

3 0

Answer:

B. $3\sqrt x -2$

Step-by-step explanation:

Option B is the correct answer

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Can someone help me with this question

mr Goodwill [35]

Answer:

53.3

Step-by-step explanation:

34^2=1156

41^2=1681

1156+1681=2837

Square root of 2837 is 53.26 which rounded to the nearest tenth is 53.3

7 0

3 years ago

Use distributive property to rewrite problem so it had only two factors. Then solve (25x9)+(75x9)=

Shalnov [3]

ANSWER

$(25\times9)+(75\times9)=9(25+75)$

$(25\times9)+(75\times9)=9(100)$

$(25\times9)+(75\times9)=900$

EXPLANATION

According to the distributive property,

$(a\times b)+(a\times c)=a(b+c)$

This implies that,

$(25\times9)+(75\times9)=9(25+75)$

$(25\times9)+(75\times9)=9(100)$

The Right Hand Side of the equation now has 2 factors.

We solve now to obtain;

$(25\times9)+(75\times9)=900$

4 0

3 years ago

Olce Question What type of notation uses these brackets {}? A. Interval B. Set

Sergio [31]

Answer:

Interval?

Step-by-step explanation:

5 0

3 years ago

Choose what the expressions below best represent within the context of the word problem. The tens digit of a number is twice the

Usimov [2.4K]

2x + x = 12
=> x =12/3 =4
so, original number is 84.

6 0

3 years ago

The equation of a circle is (x + 6)^2 + (y - 4)^2 = 16. The point (-6, 8) is on the circle.

pantera1 [17]

Answer:

y = 8 is the equation of tangent.

Step-by-step explanation:

The equation of the tangent to the circle at (-6,8) is of the form:

y = mx + c

where m is the slope of the tangent and c is the y-intercept.

The point (-6,8) lies on the circle and the tangent line as well.

Hence (-6,8) satisfies the line equation:

8 = m(-6) + c ⇒ c-6m = 8 -------------1

We know that slope of two perpendicular lines are related as:

$m_{1}\times m_{2}=-1$

At any point on the circle, the normal line at a point is always perpendicular to the tangent line at that point.

Hence :

$m_{normal} \times m_{tangent}=-1$

We can find the slope of the normal at point (-6,8) as it passes through the centre of the circle (-6,4) by using the two-points formula for slope.

$m=\frac{y_2-y_1}{x_2-x_1}$

$=\frac{8-4}{-6+6}$

= ∞

Slope of the normal is infinity and hence slope of tangent is -1/∞ = 0

Hence m=0

Putting m=0 in equation 1 we get:

c = 8

The equation of tangent line at (-6,8) is:

y = 8

6 0

3 years ago