By the pythagorean theorem, we know that (leg1)^2 + (leg2)^2 = hypotenuse^2. to see the proof refer to the following link: http://jwilson.coe.uga.edu/EMT668/EMT668.Student.Folders/HeadAngela/essay1/Pythagorean.html
plugging in what we know we have 16^2 + leg^2 = 20^2 and we find that leg = 12.
Answer:
197/ 50 or in decimal 3.94
(-2x + 3) - (7x -10)
= (-2x + 3 - 7x +10)
<h2><u>= 13 - 9x</u></h2>
Hope this will help...
Answer: the anwser is A
Step-by-step explanation:
I used a calculator lol
Answer: Rs 2,184
Explanation:
1) The statement is incomplete. The complete statement contains the information of the dimensions of both bigger and smaller cardboard boxes.
2) The dimesions of bigger cardboard boxes are 25cm * 20 cm * 5 cm
3) The dimensions of smaller cardboard boxes are 15 cm * 12 cm * 5cm
4) For bigger cardboard boxes:
length, l = 25 cm
width, w = 20 cm
height, h = 5 cm
surface of each bigger carboard box = 2 [ l*w + l*h + w*h] = 2 [25*20 + 25*5 + 20*5] cm^2 = 1450 cm^2
total surface of 250 bigger cardboard boxes = 250 * 1450 cm^2 = 3625,500 cm^2
5% of the total surface area extra = 362,500cm^2 * 5 / 100 = 18,125 cm^2
Total area for bigger cardboard boxes= 362,500 cm^2 + 18,125 cm^2 = 380,625 cm^2
5) Smaller cardboard boxes
length, l = 15 cm
width, w = 12 cm
height, h = 5 cm
surface of each smaller cardboard box = 2 [l*w + l*h + w*h] = 2 [ 15*12 + 15 * 5 + 12 * 5] cm^2 = 630 cm^2
total surface of 250 smaller cardboard boxes = 250 * 630 cm^2 = 157,500 cm^2
5 % extra = 157,500 cm^2 * 5 / 100 = 7,875 cm^2
total area for smaller cardboard boxes = 157,500 cm^2 + 7,875 cm^2 = 165,375 cm^2
6) total area of cardboard required = 380,625 cm^2 + 165,375 cm^2 = 546,000 cm^2
7) Cost of cardboard required
unit cost per area * total area = (Rs 4 / 1000cm^2) * 546,000 cm^2 = Rs 2,184.
Answer: Rs 2,184
