The equation has no solution.
<h3>How to solve the equation?</h3>
The equation given is illustrated as:
3x-2y=3 .... i
6x-4y=1 ..... ii
Multiply equation i by 6
Multiply equation ii by 3
18x - 12y = 18
18x - 12y = 3
Subtract the equations.
This will give 0. Therefore, the equations gas no solution.
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It is the line of symmetry of a parabola and divides a parabola into two equal halves that are reflections of each other about the line of symmetry.
x2=36
We move all terms to the left:
x2-(36)=0
We add all the numbers together, and all the variables
x^2-36=0
a = 1; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·1·(-36)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
x1=−b−Δ√2ax2=−b+Δ√2a
Δ‾‾√=144‾‾‾‾√=12
x1=−b−Δ√2a=−(0)−122∗1=−122=−6
x2=−b+Δ√2a=−(0)+122∗1=122=6
