I believe that 2*(4v-5) is the answer
Let the lengths of pregnancies be X
X follows normal distribution with mean 268 and standard deviation 15 days
z=(X-269)/15
a. P(X>308)
z=(308-269)/15=2.6
thus:
P(X>308)=P(z>2.6)
=1-0.995
=0.005
b] Given that if the length of pregnancy is in lowest is 44%, then the baby is premature. We need to find the length that separates the premature babies from those who are not premature.
P(X<x)=0.44
P(Z<z)=0.44
z=-0.15
thus the value of x will be found as follows:
-0.05=(x-269)/15
-0.05(15)=x-269
-0.75=x-269
x=-0.75+269
x=268.78
The length that separates premature babies from those who are not premature is 268.78 days
Answer:
answer : A
Step-by-step explanation:
hello :
Sin 42°= Cos(90°-42°)=cos(48°)......answer : A
Answer:
Step-by-step explanation:
<u>We have similar triangles here.</u>
- BC║DE, AB║AD and AC║AE ⇒ ΔADE ~ ΔABC
<u>The ratio of corresponding sides of similar triangles is same:</u>
- BC/DE = AC/AE
- BC / 2 = 30/3
- BC / 2 = 10
- BC = 2*10
- BC = 20 m
Answer:
150 miles
Step-by-step explanation:
If 1/2 of an inch is 20 miles, we can assume that 1/4 of an inch is 10 miles, since half of 1/2 is 1/4 and 1/2 of 20 is 10.
Equipped with this information, we can divide 3 by 1/2 or multiply 3 by the reciprical, 2/1 to get how much we should multiply 20 by.
3*2=6
20*6=120
Then we can multiply 10 by 3 and add that on our answer, since there are still 3/4s left and 1/4=10 miles.
10*3=30
120+30=150
The actual distance is 150 miles.
Hope this helps!