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Fynjy0 [20]
3 years ago
10

How do i solve F (-1) = please show how its done

Mathematics
2 answers:
Anvisha [2.4K]3 years ago
8 0
 f(x) = x² - 4x + 3
f(-1) = (-1)² - 4(-1) + 3
f(-1) = 1 + 4 + 3
f(-1) = 5 + 3
f(-1) = 8
seraphim [82]3 years ago
7 0
Whats the equation? but when ever you see f( ), what ever is in the parenthesis just plug into x
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\bf 0.444444444\overline{4}\impliedby \textit{and keeps on going}\\\\
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\textit{let's say }\boxed{x=0.444444444\overline{4}}\quad \textit{ thus }10\cdot x=4.44444444\overline{4}
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\textit{wait a minute! }4.44444444\overline{4}\textit{ is really just }4+0.444444444\overline{4}

\bf \textit{but we know }x=0.444444444\overline{4} \textit{ so then }4+0.444444444\overline{4}=\boxed{4+x}
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\textit{wait a second! }10\cdot x\implies 10x=4.444444444\overline{4}=4+x
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thus\qquad 10x=4+x\implies 10x-x=4\implies 9x=4\implies \boxed{x=\cfrac{4}{9}}

you can check in your calculator.

anyhow, to get the "recurring decimal to fraction", you start by setting to some variable, "x" in this case, then move the repeating part to the left of the point by multiplying it by some power of 10, and then do the equating.
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Answer:

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