80, 84, 79, 44, 87, 73, 89, 90, 82, 89, 93, 97, 77, and 71 whats the mean
Contact [7]
Answer:
sum up the numbers and divide by the numbers of values.
80+84+79+44+87+73+89+90+82+89+93+97+77+71 / 14
1135/14
= 81•1 is the mean
Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
Answer:
Tan C = 3/4
Step-by-step explanation:
Given-
∠ A = 90°, sin C = 3 / 5
<u>METHOD - I</u>
<u><em>Sin² C + Cos² C = 1</em></u>
Cos² C = 1 - Sin² C
Cos² C = 
Cos² C = 
Cos² C = 
Cos C = 
Cos C = 
As we know that
Tan C = 
<em>Tan C = 
</em>
<em>Tan C = 
</em>
<u>METHOD - II</u>
Given Sin C = 
therefore,
AB ( Height ) = 3; BC ( Hypotenuse) = 5
<em>∵ ΔABC is Right triangle.</em>
<em>∴ By Pythagorean Theorem-</em>
<em>AB² + AC² = BC²</em>
<em>AC² </em><em>= </em><em>BC² </em><em>- </em><em> AB</em><em>² </em>
<em>AC² = 5² - 3²</em>
<em>AC² = 25 - 9</em>
<em>AC² = 16</em>
<em>AC ( Base) = 4</em>
<em>Since, </em>
<em>Tan C = 
</em>
<em>Tan C = 
</em>
<em>Hence Tan C = </em>
<em />
Well, 10 can go into 56, 5 times, so your whole number would be 5.
Then 50 (where did i get 50 from? 5 times the ten is 50) minues 56 is 6. So it would be :
5 and 6/10 (your denominator stays the same)
But it needs o be simplafied to its lowest terms. They are both divisable by 2, SOO 6 divided by 2 is 3, and 10 divided by 2 is 5 So, your new fraction is:
5 and 3/5 in which it cant be simplafied anymore.
<em>~ 5 3/5 </em><em>is your answer :)</em>
Let 
be the dimensions of the rectangle. We know the equations for both area and perimeter:
So, we have the following system:
From the second equation, we can deduce
Plug this in the first equation to get
Refactor as
And solve with the usual quadratic formula to get
Both solutions are feasible, because they're both positive.
If we chose the positive solution, we have
If we choose the negative solution, we have
So, we're just swapping the role of 
and 
. The two dimensions of the rectangle are 
and 
