I need help with problem 6 please. I tried to do it, but I don't know how :(
1 answer:
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Area of the given rhombus = 498.83 ft²
Solution:
Given figure is a rhombus ABCD.
BE = 12 ft and ∠BAE = 30°
Property of rhombus:
Diagonals bisect each other at right angles.
In ΔAEB, ∠BAE = 30°, ∠AEB = 90° and BE = 12 ft
Do cross multiplication, we get
AB = 24 ft
Using Pythagoras theorem,
Taking square root on both sides, we get
ft
AC =
Area of the rhombus =
= 498.83 ft²
Area of the given rhombus = 498.83 ft²