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3 years ago

13

The price of gold rose from $790 per ounce to $860 per ounce what percent increase does this amount represent round to the neare

st 10th of a percent

1 answer:

neonofarm [45]3 years ago

8 0

There’s so many number

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Angle relationships worksheet #2 10-17

lbvjy [14]

That does not make any since...

3 0

3 years ago

1. Solve the equation using the zero-product property.<br> -x(5x – 4) = 0

Oxana [17]

Answer:

x = 0, 4/5

Step-by-step explanation:

The zero-product property states that if the product of a and b is zero, then either a = 0, b = 0, or both terms equal zero

Here our a term is -x and our b term is (5x - 4)
Setting each term equal to zero and solving for x we get
-x = 0 → x = 0
5x - 4 = 0 → 5x = 4 → x = 4/5

6 0

2 years ago

If 2a+b=6 and a−6=b, what is the value of a?

earnstyle [38]

Step-by-step explanation:

Given

2a + b = 6......equation 1

a - 6 = b

a = b + 6........equation 2

Putting equation 2 in equation 1

2 ( b + 6 ) + b = 6

2b + 12 + b = 6

3b = 6 - 12

3b = - 6

b = - 6 / 3

Therefore b = - 2

Now

a = - 2 + 6 = 4

hope it will help :)

3 0

3 years ago

Read 2 more answers

A man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream. Fin

pochemuha

The speed of the current is 40.34 mph approximately.

<u>SOLUTION: </u>

Given, a man can drive a motorboat 70 miles down the Colorado River in the same amount of time that he can drive 40 miles upstream.

We have to find the speed of the current if the speed of the boat is 11 mph in still water. Now, let the speed of river be a mph. Then, speed of boat in upstream will be a-11 mph and speed in downstream will be a+11 mph.

And, we know that, $\text{ distance } =\text{ speed }\times \text{ time }$

$\begin{array}{l}{\text { So, for upstream } \rightarrow 40=(a-11) \times \text { time taken } \rightarrow \text { time taken }=\frac{40}{a-11}} \\\\ {\text { And for downstream } \rightarrow 70=(a+11) \times \text { time taken } \rightarrow \text { time taken }=\frac{70}{a+11}}\end{array}$

We are given that, time taken for both are same. So $\frac{40}{a-11}=\frac{70}{a+11}$

$\begin{array}{l}{\rightarrow 40(a+11)=70(a-11)} \\\\ {\rightarrow 40 a+440=70 a-770} \\\\ {\rightarrow 70 a-40 a=770+440} \\\\ {\rightarrow 30 a=1210} \\\\ {\rightarrow a=40.33}\end{array}$

8 0

3 years ago

ILL GIVE BRAINLIEST

labwork [276]

Answer:

I can't read the question it's too blurry

7 0

2 years ago