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3 years ago

A roller coaster descended 32.3 ft in one minute. How would you show this using an integer?

Mathematics

2 answers:

Aliun [14]3 years ago

8 0

The answer is A because the roller coaster is decreasing in ft.

emmainna [20.7K]3 years ago

5 0

Answer:

Step-by-step explanation:

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Keiko, Abdul, and Bob have a total of $82 in their wallets. Keiko has $7 more than Abdul. Bob has 3 times what Abdul has. How mu

dlinn [17]

Answer:

abdul has 15

keiko has 22

bob has 45

Step-by-step explanation:

82= a+7+3a+a

75=a+3a+a

75=5a

15=a

15=abdul

15+7=keiko

3(15)=bob

8 0

3 years ago

It takes 16 sections of carpet to cover 1 classroom floor. Tyler wants to know how many sections of carpet are needed for 6 clas

katovenus [111]

If 1 classroom uses 16 sections, then 6 classrooms would use :
6 * 16 = 96 sections

and 14 classrooms would use : 14 * 16 = 224 sections

4 0

4 years ago

Prime number after 167, 118, 82, 57, 41,

Fiesta28 [93]

The prime numbers after 167, 118, 82, 57, 41 are 37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2.

Prime numbers are numbers that are divisible by 1 and itself.

This are number greater than one with only two factors which are 1 and itself.

In other words, this number, when they are divided by another number other

than 1 or itself , one will get a remainder that is not zero.

Example of prime numbers are 2, 5, 7, 11, 13 etc.

The prime numbers after 167, 118, 82, 57, 41 are as follows:

37, 31, 29, 23, 19, 17, 13, 11, 7, 5, 3, 2.

learn more about prime number here: brainly.com/question/26013414

8 0

3 years ago

Find a particular solution to the nonhomogeneous differential equation y??+4y?+5y=?10x+e^(?x).

Firdavs [7]

Answer:

A) Particular solution:

$2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

B) Homogeneous solution:

$y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))$

C) The most general solution is

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

Step-by-step explanation:

Given non homogeneous ODE is

$y''+4y'+5y=10x+e^{-x}---(1)$

To find homogeneous solution:

$D^{2}+4D+5=0\\D^{2}+4D+4-4+5=0\\\\(D+2)^{2}=-1\\D+2=\pm iD=-2 \pm i\\y_{h}=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))---(2)$

To find particular solution:

$y_{p}=Ax+B+Ce^{-x}\\\\y'_{p}=A-Ce^{-x}\\y''_{p}=Ce^{-x}\\$

Substituting $y_{p},y'_{p},y''_{p}$ in (1)

$y''_{p}+4y'_{p}+5y_{p}=10x+e^{-x}\\Ce^{-x}+4(A-Ce^{-x})+5(Ax+B+Ce^{-x})=10x+e^{-x}\\$

Equating the coefficients

$5Ax+2Ce^{-x}+4A+5B=10x+e^{-x}\\5A=10\\A=2\\4A+5B=0\\B=-\frac{4A}{5}B=-\frac{8}{5}2C=1\\C=\frac{1}{2}\\So,\\y_{p}=2x+\frac{1}{2}e^{-x}-\frac{8}{5}---(3)\\$

The general solution is

$y=y_{h}+y_{p}$

from (2) ad (3)

$y=e^{-2x}(c_{1}cos(x)+c_{2}sin(x))+2x+\frac{1}{2}e^{-x}-\frac{8}{5}$

6 0

3 years ago

HELP!!!!!!!!!!!!!!!!!

jek_recluse [69]

Answer:

option A

Step-by-step explanation:

the statement tell us that she slides the triangle 2 units down, so the vertical axis is the one that we are going to modify

we have the points: (1,2), (3,3) and (4,1)

so to these points we subtract "2" to the variable Y

I mean:

(1,2): 2-2=0

(3,3): 3-2=1

(4,1): 1-2=-1

finally we have:

(1,0), (3,1) and (4,-1)

7 0

3 years ago