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stiv31 [10]
3 years ago
11

Factorize the algebraic expression:10y²+13y-3​

Mathematics
1 answer:
laila [671]3 years ago
4 0
<h2>⟰ <u>A</u><u>N</u><u>S</u><u>W</u><u>E</u><u>R</u> ⟰</h2>

<h2>U R ANS IS IN THE PIC !!</h2>

<h2>HOPE IT HELPS U!!!!!( :</h2>

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Jenny bought 3 CDs that were each the same price. Including sales tax, she paid a total of $45.30 Of that total, $1.50 was tax.
enot [183]

Answer:

$13.6

Step-by-step explanation:

Jane bought 3 CDs that were each the same price. So let the price of each CD be ‘x’.

It is given that including sales tax, she paid a total of $45.30.

Also each CD had a tax of $1.50. We need to find out what the price of each CD was before tax.

Since the tax for all 3 CDs was same, the total amount of tax that she paid was:

3 * 1.50 = 4.50

Therefore the total tax on 3 CDs is $4.50

Since we already know the total price she paid for the CDs including taxes, we can find the price of each CD by the following way:

3x + 4.50 = 45.30

3x = 45.30 - 4.50

3x = 40.8

x = 13.6

Therefore the price of each CD before tax is $13.6.

5 0
3 years ago
1/6d + 2/3 = 1/4(d-2)
xxMikexx [17]
D = 14

1/6d + 2/3 = 1/4d - 1/2
2d + 4*2 = 3d - 6
2d - 3d = -6-8
-d = -14
d = 14
4 0
3 years ago
Find the value of x. Geomotary triangles
Aleonysh [2.5K]
X/15=4/16 def of similar triangle by AAA
x = 60/16=5/2
8 0
3 years ago
What is the value of x ?
miv72 [106K]

the answer is 63 because 63*2=126 and 126+54=180 and all triangles add up to 180

7 0
2 years ago
Read 2 more answers
Of all sixth graders, 70% sent a text message yesterday. Ten trials of a simulation are conducted and the data are recorded belo
Effectus [21]

Answer:

80%

Step-by-step explanation:

According to the given data, the numbers 0 through 6 represent students who sent a text yesterday while the numbers 7 through 9 represent students who did not send a text yesterday.

Based on this key, we will calculate the number of students who sent the text yesterday and the number of students who did not sent the text yesterday.

The given data is: 62072, 34570, 80983, 04292, 83150, 36330, 96268, 14077, 77985, 13511

For each group we will identify how many students sent the text and how many students did not. According to the key, a number from 0 to 6 will be counted as a student who sent the text and a number from 7 to 9 will be counted as a student who did not send the text. Students who did not sent the text are made bold in the groups below.

62072:  4 students sent the text, 1 did not

34570:  4 students sent the text, 1 did not

80983:  2 students sent the text, 3 did not

04292:  4 students sent the text, 1 did not

83150:   4 students sent the text, 1 did not

36330:  All 5 students sent the text

96268:  3 students sent the text, 2 did not

14077:   3 students sent the text, 2 did not

77985:  1 student sent the text, 4 did not

13511:    All 5 students sent the text

We need to find the probability that 3 or more of a group of 5 students randomly selected will send a text today.

From the given groups, the number of groups where 3 or more students sent a text = 8

This represents our number of favorable or desired outcomes.

Total number of possible outcomes is the total number of groups = 10

Since, probability is defined as the ratio of number of favorable outcomes to total number of outcomes, based on the simulated data  the probability that 3 or more of a group of 5 students randomly selected will send a text today will be = \frac{8}{10}=0.80=80\%

Thus, based on the simulated data there is 80% probability that 3 or more of a group of 5 students randomly selected will send a text today

5 0
3 years ago
Read 2 more answers
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