Answer:
A & B
Step-by-step explanation:
Both to the same decimal place
Please, use parentheses to enclose each fraction:
y=3/4X+5 should be written as <span>y=(3/4)X+5
Let's eliminate the fraction 3/4 by multiplying the above equation through by 4:
4[y] = 4[(3/4)x + 5]
Then 4y = 3x + 20
(no fraction here)
Let 's now solve the system
4y=3x + 20
4x-3y=-1
We are to solve this system using subtraction. To accomplish this, multiply the first equation by 3 and the second equation by 4. Here's what happens:
12y = 9x + 60 (first equation)
16x-12y = -4, or -12y = -4 - 16x (second equation)
Then we have
12y = 9x + 60
-12y =-16x - 4
If we add here, 12y-12y becomes zero and we then have 0 = -7x + 56.
Solving this for x: 7x = 56; x=8
We were given equations
</span><span>y=3/4X+5
4x-3y=-1
We can subst. x=8 into either of these eqn's to find y. Let's try the first one:
y = (3/4)(8)+5 = 6+5=11
Then x=8 and y=11.
You should check this result. Subst. x=8 and y=11 into the second given equation. Is this equation now true?</span>
Step-by-step explanation:
you need to attach the picture so people can answer your question
Answer:
Step-by-step explanation:
Let s be the number of pages in each issue of the sports magazine, and t be the number of pages in each issue of the technology magazine.
We have been given that Each issue of the sports magazine has 18 fewer pages than each issue of the technology magazine. We can represent this information in an equation as:
We are also given that sports magazine prints 12 issues per year, so the total number of pages in all the issues of sports magazine will be 12*s.
We are given that a technology magazine prints 10 issues per year, so the total number of pages in all the issues of technology magazine will be 10*s.
Further, the total number of pages in all the issues of the sports magazine for one year is 32 more than the total number of pages in all the issues of the technology magazine for one year.
We can represent this information in an equation as:
Therefore, our desired system of equations will be: