Question

Is 48 a perfect cube? Explain your reasoning.

Answer 1

Answer:

No

Reasoning:

If something is a perfect cube, it is able to be put under a cube root ($\sqrt[3]{..}$) and will result in an integer (a non-decimal number > 0, basically).

So let's calculate $\sqrt[3]{48}$, and see if the result is an integer.

$\sqrt[3]{48}$ = 3.634.......

As you can see, the result is not an integer, therefore 48 is not a perfect cube.