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fgiga [73]
2 years ago
6

Is 48 a perfect cube? Explain your reasoning.

Mathematics
1 answer:
Ksivusya [100]2 years ago
8 0

Answer:

No

Reasoning:

If something is a perfect cube, it is able to be put under a cube root (\sqrt[3]{..}) and will result in an integer (a non-decimal number > 0, basically).

So let's calculate \sqrt[3]{48}, and see if the result is an integer.

\sqrt[3]{48} = 3.634.......

As you can see, the result is not an integer, therefore 48 is not a perfect cube.

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