Is 48 a perfect cube? Explain your reasoning.
1 answer:
Answer:
No
Reasoning:
If something is a perfect cube, it is able to be put under a cube root (![\sqrt[3]{..}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B..%7D)
) and will result in an integer (a non-decimal number > 0, basically).
So let's calculate ![\sqrt[3]{48}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B48%7D)
, and see if the result is an integer.
= 3.634.......
As you can see, the result is not an integer, therefore 48 is not a perfect cube.
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The degree is the largest exponent on the variable.
Degree: 5
Answer:
40.49cm²
Step-by-step explanation:
I hope it helps
X+3y=14
-x. -x
3y=-x+14
Divide them all by 3
Y=-x/3+14/3
Y-intercept= 1/3
First, 10 to the second power equals to 100. 100 divided by 3 equals to 33.33. 33.33 x 7 equals to 233.33. So the answer is 233.33.
