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Karolina [17]
3 years ago
9

The probability that a lab specimen contains high levels of contamination is 0.10. A group of 5 independent samples are checked.

Round your answers to four decimal places (e.g. 98.7654).
(a) What is the probability that none contain high levels of contamination?
(b) What is the probability that exactly one contains high levels of contamination?
(c) What is the probability that at least one contains high levels of contamination?
Mathematics
1 answer:
zhannawk [14.2K]3 years ago
3 0

Answer with Step-by-step explanation:

In case of Bernoulli trails

The probability that a random variable occurs 'r' times in 'n' trails is given by

P(E)=\binom{n}{r}p^r(1-p)^{n-r}

where

'p' is the probability of success of the event

Part a)

probability that no contamination occurs can be found by putting r = 0

Thus we get

P(E_1)=\binom{5}{0}0.1^0(1-0.1)^{5}=0.5905

part b)

The probability that at least 1 contamination occurs is given by

P(E)=1-(1-p)^{n}

Applying values we get

P(E_2)=1-(1-0.1)^{5}=0.4096

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Answer:

Let X be the event of feeling secure after saving $50,000,

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Since, the binomial distribution formula,

P(x=r)=^nC_r p^r q^{n-r}

Where, ^nC_r=\frac{n!}{r!(n-r)!}

If 8 households choose randomly,

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P(X=5)=^8C_5 (0.4)^5 (0.6)^{8-5}

=56(0.4)^5 (0.6)^3

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(b) the probability of the number that say they would feel secure is more than five

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(c) the probability of the number that say they would feel secure is at most five

P(X\leq 5) = P(X=0) + P(X=1) + P(X=2) + P(X=3) + P(X=4) + P(X=5)

=^8C_0 (0.4)^0(0.6)^{8-0}+^8C_1(0.4)^1(0.6)^{8-1}+^8C_2 (0.4)^2 (0.6)^{8-2}+8C_3 (0.4)^3 (0.6)^{8-3}+8C_4 (0.4)^4 (0.6)^{8-4}+8C_5(0.4)^5 (0.6)^{8-5}

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Good evening ,

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