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drek231 [11]
3 years ago
7

PLEASE HELP

Mathematics
1 answer:
Georgia [21]3 years ago
6 0

Answer:

Option A and Option C

Step-by-step explanation:

Given:

IJ ≅ LM

∠J ≅ ∠M

To Prove:

ΔHIJ ≅ ΔKLM

              Statements                           Reasons

1). IJ ≅ LM                               1). Given

2). ∠J = m∠M                          2). Given

3). ΔHIJ ≅ ΔKLM                    3). By HA property Or AAS property of

                                                    congruence

Therefore, Option A and Option C are the correct options.

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It took Lester 10 minutes to walk. to the skate park. He then rode his skateboard for 35 minutes. Lester finished riding at 10:4
sergiy2304 [10]
10min + 35min = 45min

Lester left 45min before 10:45AM

he left at 10AM
7 0
3 years ago
Read 2 more answers
I solved it myself and my result is (n+1)/n. Why is that 1/2 there? An explanation would be great if possible. Thanks!
katovenus [111]

Answer:

The product of (k + 1) series starts with 3 (because k = 2) and you need 2 to be multiplied to this in order to get (n + 1)!

Therefore you need to multiply 2 and 1/2 to make it right. 2 completes the factorial and 1/2 remains.

Hope it was clear explanation.

6 0
3 years ago
Find the percent of decrease from 280 to 210. Round to the nearest tenth of a percent, if necessary.
Vlada [557]
To find the decreased percentage,here's what we can do:
\frac{originl \: value - new \: value}{originl \: value}  \times 100\%

In this case,the eqaution would be:
\frac{280 - 210}{280}  \times 100\% \\  =  \frac{70}{280}  \times 100\% \\  =  \frac{1}{4}  \times 100\% \\  = 25\%
Hope it helps!
5 0
4 years ago
Select all the correct graphs.<br> Which graphs are the graphs of even functions?
natali 33 [55]

Answer:

I think it the first one is

7 0
2 years ago
The Ohio Department of Agriculture tested 203 fuel samples across the state in 1999 for accuracy of the reported octane level. F
OlgaM077 [116]

Answer:

The Sample size is 1918.89035

Step-by-step explanation:

Consider the provided information.

It is given that 14 out of 105 samples failed.

Therefore p = 14/105 = 0.13 3... and q=1-0.133=0.867

Samples would be needed to create a 99 percent confidence interval.

Subtract the confidence level from 1, then divide by two.

\frac{(1 -0.99)}{2}=0.005

By standard normal table z=2.5758≈2.58

Calculate the sample size as:

n=\frac{z^2pq}{e^2}

Where,  e is the margin of error,

Substitute the respective values.

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Hence, the Sample size is 1918.89035

4 0
3 years ago
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