Option (A) identifies them correctly.
During Meosis 2 daughter cells are formed from a single cell and the chromosomes are equally divided in both the cells.
So, Cell P had 60 chromosome, after miosis 2 daughter cells of each having 30 chromosomes formed, and again after Miosis of from each of those 2 those daughter cells, 2 more daughter cells are formed with equal naumber of chtomosome which equals 15.
Answer:1,3,4
Explanation:
Antibiotics, Antiparasitic, Antifungal
Answer:
<u>1. type IV hypersensitivity: delayed-type hypersensitivity. </u>
<u>2. type I hypersensitivity: IgE </u>
<u>3. type II hypersensitivity: IgG </u>
<u>4. type III hypersensitivity: immune complexes </u>
Explanation:
Type IV hypersensitivity is cell mediated hypersensitivity rather than antibodies as in all other types of hypersensitivities. It is also known as delayed type hypersensitivity because it usually respond in 2-3 days via T-Lymphocytes rather than antibodies like IgE or IgG. So we can say that in option 5 is mismatched as it relates type IV to IgG antibodies.
I think that it’s A, D, and F
-the particles do not have a charge
-movement across membrane doesn’t require additional energy
-the particles crossing could be oxygen or water
The other cat has (I dont know what letters your using so I'm going to use 'c'.
The first genotype looks like this cc
the other Parent has to have a donomint trate as well as the recessiv Cc