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3 years ago

How does technology affect the economy

Mathematics

1 answer:

lys-0071 [83]3 years ago

4 0

Answer:

In economics, it is widely accepted that technology is the key driver of economic growth of countries, regions and cities. ... Technological progress allows for the more efficient production of more and better goods and services, which is what prosperity depends on.

i didn't know if you wanted the positive or negatives affects

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Can someone smart help me with this plz:)

insens350 [35]

Answer:

Step-by-step explanation:

Sum of all angles of triangle = 180°

6p + 6p + 3 p = 180

15p = 180

p = 180/15

p = 12

Angles are:

6p = 6*12 = 72°

3p = 3*12 = 36°

Angles are: 72°, 72° , 36°

6 0

3 years ago

If an area of a circle is 58 square feet find the circumference

mash [69]

26.99 square feet or just feet

5 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .