Let x be the distance from Syracuse where they pass. The first car travels a distance of x in time x/65 while the second car travels a distance 240-x in time (240-x)/55. They pass at the same time after leaving their starting points so x/65=(240-x)/55.
Cross-multiplying we get: 55x=65(240-x)=15600-65x, 120x=15600, x=15600/120=130 miles.
They pass 130 miles from Syracuse.
It’s 2 and 3 bc 6a+12 and then 3(2a+4) and you need to distribute for that so 3 times 2a equals 6a and 3 times 4 equals 12 so you get 6a+12
The riddle answer is 24.
A riddle for the number 68 is: 12 more than 14 times 4
Answer:
41ft is your answer
left side=√(12²+12²)=16.97=17ft
perimeter=sum of all side=12+12+17=41ft
This is very sloppy but u hope it helps
