Answer:
0% probability cab tires depths would be shallower than 0.25cm.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability cab tires depths would be shallower than 0.25cm.
This probability is the pvalue of Z when X = 0.25. So



has a pvalue of 0.
0% probability cab tires depths would be shallower than 0.25cm.
Answer:
The number is: "
12 ".
____________________________________ Let "x" represent "the unknown number" (for which we wish to solve.
The expression:

x <span>− 6 = 2 ; Solve for "x" ;
</span>
_______________________________________________Method 1) Add "6" to EACH SIDE of the equation;
_______________________________________________ →

x − 6 + 6 = 2 + 6 ;
to get:
→

x = 8 ;
______________________________________________Multiply each side of the equation by "

" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________ →
*

x = 8 *

;
→ x = 8 *

;
=

*

;
=

;
=

;
= <span>
1<span>
2 .</span></span>
______________________________________________ x = 12 .
______________________________________________Method 2)______________________________________________
x − 6 = 2 ; Solve for "x" ;
Add "6" to EACH SIDE of the equation;
_______________________________________________ →

x − 6 + 6 = 2 + 6 ;
to get:
→

x = 8 ;
______________________________________________Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
→ 3 *

x = 8 * 3 ;
→

*

x = 8 * 3 ;
→

x = 8 * 3
→

x = 24 ;
→ 2x = 24 ;
→ Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" :
2x / 2 = 24 / 2 ;
x = 12 .
__________________________________________________Method 3).__________________________________________________
x − 6 = 2 ; Solve for "x" ;
_______________________________________________Add "6" to EACH SIDE of the equation;
_______________________________________________ →

x − 6 + 6 = 2 + 6 ;
to get:
→

x = 8 ;
______________________________________________Now, divide each side of the equation by "

" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________{

x } / {

} = 8 / {

} ;
to get: x = 8 / {

} ;
= 8 * (

;
=

*

;
=

;
=

;
=
12 ;
___________________________________________ x = 12 .
___________________________________________NOTE: Variant: (in "Methods 2 & 3") :
___________________________________________At the point where:
___________________________________________ = 8 * (

) ;
=

*

;
__________________________________________ We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________ {since: "8÷2 = 4" ; and since: "2÷2 =1" } ;
__________________________________________and we can rewrite the expression:
__________________________________________ 
*

;
__________________________________________as:

*

;
__________________________________________which equals:
__________________________________________→

;
=

;
=
12 .
__________________________________________ x = 12 .
__________________________________________Answer:
The number is: "
12 ".
__________________________________________
Answer:X=-37
Step-by-step explanation:
We can set it up like this, where <em>s </em>is the speed of the canoeist:

To make a common denominator between the fractions, we can multiply the whole equation by s(s-5):
![s(s-5)[\frac{18}{s} + \frac{4}{s-5} = 3] \\ 18(s-5)+4s=3s(s-5) \\ 18s - 90+4s=3 s^{2} -15s](https://tex.z-dn.net/?f=s%28s-5%29%5B%5Cfrac%7B18%7D%7Bs%7D%20%2B%20%5Cfrac%7B4%7D%7Bs-5%7D%20%3D%203%5D%20%5C%5C%2018%28s-5%29%2B4s%3D3s%28s-5%29%20%5C%5C%2018s%20-%2090%2B4s%3D3%20s%5E%7B2%7D%20-15s)
If we rearrange this, we can turn it into a quadratic equation and factor:

Technically, either of these solutions would work when plugged into the original equation, but I would use the second solution because it's a little "neater." We have the speed for the first part of the trip (9 mph); now we just need to subtract 5mph to get the speed for the second part of the trip.

The canoeist's speed on the first part of the trip was 9mph, and their speed on the second part was 4mph.